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klasskru [66]
3 years ago
6

A rectangular room is 15 meters longer than it is wide, and it’s perimeter is 26 meters. Find the dimensions of the room

Mathematics
1 answer:
Julli [10]3 years ago
5 0

Answer:

the room is -1m by 14m

Step-by-step explanation:

what you do to find it is first find x.

the perimeter is 26, and one side is 15 meters longer than the other(twice).

So the equation is:

x + (x + 15) + x + (x + 15) = 26

2x + 2(x + 15) = 26

2x + 2x + 30 = 26

4x + 30 = 26

26 - 4x = 30

26 - 26 - 4x = 30 - 26

-4x = 4

-4x/-4 = 4/-4

x = -1

Now we have two sides of the room. Now we want the 15m longer ones...

-1 + 15 = 14

so the dimensions are -1 by 14, or -1x14

Hope this helps. if this is the best answer, mark Brainliest.

If not, hope it helps anyway.

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Step-by-step explanation:

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3 years ago
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

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alexgriva [62]
110 (goal) - 50 (base pay) = 60 (pay from sales only)

60 (total pay from sales) / 3 (cost per individual sale) = 20 (qty of sales)
7 0
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