A rectangular room is 15 meters longer than it is wide, and it’s perimeter is 26 meters. Find the dimensions of the room

Mathematics

1 answer:

Julli [10]3 years ago

5 0

Answer:

the room is -1m by 14m

Step-by-step explanation:

what you do to find it is first find x.

the perimeter is 26, and one side is 15 meters longer than the other(twice).

So the equation is:

x + (x + 15) + x + (x + 15) = 26

2x + 2(x + 15) = 26

2x + 2x + 30 = 26

4x + 30 = 26

26 - 4x = 30

26 - 26 - 4x = 30 - 26

-4x = 4

-4x/-4 = 4/-4

x = -1

Now we have two sides of the room. Now we want the 15m longer ones...

-1 + 15 = 14

so the dimensions are -1 by 14, or -1x14

Hope this helps. if this is the best answer, mark Brainliest.

If not, hope it helps anyway.

You might be interested in

SC_2, 4) and T (3,9).<br> The midpoint is MC). The distance between S and T is about

schepotkina [342]

Answer:

Midpoint is (0.5,6.5)

the distance is 7.1

Step-by-step explanation:

hope this helps u have a nice day :)

4 0

3 years ago

Sin 1 + sin 2 + sin3 .................+ sin 360 = ?

lesya [120]

Assuming that arcs are given in degrees, call S the following sum:

S = sin 1° + sin 2° + sin 3° + ... + sin 359° + sin 360°

Rearranging the terms, you can rewrite S as

S = [sin 1° + sin 359°] + [sin 2° + sin 358°] + ... + [sin 179° + sin 181°] + sin 180° +
+ sin 360°

S = [sin 1° + sin(360° – 1°)] + [sin 2° + sin(360° – 2°)] + ...+ [sin 179° + sin(360° – 179)°]
+ sin 180° + sin 360° (i)

But for any real k,

sin(360° – k) = – sin k

then,

S = [sin 1° – sin 1°] + [sin 2° – sin 2°] + ... + [sin 179° – sin 179°] + sin 180° + sin 360°

S = 0 + 0 + ... + 0 + 0 + 0 (... as sin 180° = sin 360° = 0)

S = 0

Each pair of terms in brackets cancel out themselves, so the sum equals zero.

∴ sin 1° + sin 2° + sin 3° + ... + sin 359° + sin 360° = 0 ✔

I hope this helps. =)

Tags: <em>sum summatory trigonometric trig function sine sin trigonometry</em>

4 0

3 years ago

3y+10x-54=0 5y-2x-34=0<br><br> x=<br><br> y=

Blababa [14]

<h3>Answer:</h3><h2>x = 3 and y = 8 → (3, 8)</h2><h3>Step-by-step explanation:</h3>

$\left\{\begin{array}{ccc}3y+10x-54=0&\text{add 54 to both sides}\\5y-2x-34=0&\text{add 34 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}3y+10x=54\\5y-2x=34&\text{multiply both sides by 5}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3y+10x=54\\25y-10x=170\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ 28y=224\qquad\text{divide both sides by 28}\\.\ \ \ \ \ \ \ \dfrac{28y}{28}=\dfrac{224}{28}\\.\ \ \ \ \ \ \ \boxed{y=8}$

$\text{put the value of y to the first equation}\\\\3(8)+10x=54\\24+10x=54\qquad\text{subtract 24 from both sides}\\24-24+10x=54-24\\10x=30\qquad\text{divide both sides by 10}\\\dfrac{10x}{10}=\dfrac{30}{10}\\\boxed{x=3}$