Question

What is the fifth term of the sequence whose first term is 10 and whose common ratio is 1/2?

Answer 1

Answer:

$\frac{5}{8}$

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = a₁$(r)^{n-1}$

where a₁ is the first term and r the common ratio

here a₁ = 10 and r = $\frac{1}{2}$, thus

$a_{5}$ = 10 × $(1/2)^{4}$ = 10 × $\frac{1}{16}$ = $\frac{5}{8}$