Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
So since the kitchens long is wide x 2 if you add the 2 longs it makes a wide so you end up with 3 wides technically. So you divide 84 by 3 and u get 28 so make your 2 wides 28. Then u divide 28 by 2 to get 14 so your longs are 14 and your wides are 28 if u add it all together it’s 84.
Answer:
what is the problem
Step-by-step explanation:
i need picture
The half-life of the given exponential function is of 346.57 years.
<h3>What is the half-life of an exponential function?</h3>
It is the value of t when A(t) = 0.5A(0).
In this problem, the equation is:
.
In which t is measured in years.
Hence the half-life is found as follows:
t = 346.57 years.
More can be learned about exponential functions at brainly.com/question/25537936
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Answer:
t = 2
Step-by-step explanation:
5t - 4 = 6
make t the subject
move -4 to the other side of the equal sign
5t = 6 + 4
5t = 10
t = 10/5
<u>t = 2</u>
