All categories

3 years ago

Which set of ordered pairs does not represents a function?

Mathematics

2 answers:

Rus_ich [418]3 years ago

6 0

Answer:

The first set of ordered pairs is a function, because no two ordered pairs have the same first coordinates with different second coordinates. The second example is not a function, because it contains the ordered pairs (1,2) and (1,5). These have the same first coordinate and different second coordinates.

Nat2105 [25]3 years ago

5 0

Answer:

The first option.

Step-by-step explanation:

You cannot repeat the x value if it is a function. The x value of 2 is repeated in the first option.

You might be interested in

An animal shelter uses 41 cups of food each day to feed the dogs and cats. Each dog eats 2 cups per day. The cats eat a total of

nignag [31]

Answer:

The equation that can be used to find d is $2d+17=41$

$d=12\ dogs$

Step-by-step explanation:

Let

d -----> the number of dogs

we know that

The linear equation that represent this situation is

$2d+17=41$

Solve for d

Subtract 17 both sides

$2d=41-17$

$2d=24$

Divide by 2 both sides

$d=12\ dogs$

6 0

3 years ago

Is 2.389746 rational or irrational

Nina [5.8K]

Answer:

it's rational

Step-by-step explanation:

6 0

3 years ago

Angelo is 7 years younger than his brother Jayson. If Jayson's age is J, what expression stand's for Angelo's age?

DanielleElmas [232]

Answer: j-7

Step-by-step explanation:

So Jayson is J

Angelo is 7 years younger than him so j-7

5 0

3 years ago

The "mammals" data set in the "MASS" library contains the result of a study of sleep in mammal species. 1 2 Load the "mammals" d

dusya [7]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

The probability that the random you randomly select species that are greater than 200 kg is = 7/62

Step-by-step explanation:

Step One: Load the data set in to the R work space

data(mammals,package="MASS")

attach(mammals)

Step 2 : Obtain the list of the species that are greater than 200 and store it on y variable.

y <- subset(mammals,body>200)

Step Three : Obtain the total size

nrow(mammals)

Step Four : Obtain the sum of species greater than 200

sum(body > 200)

total size = 62

size with body > 200 = 7

hence

required probability = 7/62

7 0

3 years ago

A student got 78 marks out of a possible 120. Express the students mark as a percentage

statuscvo [17]

Answer:

65%

Step-by-step explanation:

78/120=13/20

13/20=65/100

65/100=65%

8 0

3 years ago

Read 2 more answers