1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Afina-wow [57]
2 years ago
10

_C2H5OH + _O2–>_CO2 + _H2O How do u balance in the equation

Chemistry
1 answer:
Komok [63]2 years ago
8 0

Answer:

C2H5OH +

3

O2 -->

2

CO2 +

3

H2O

(COMBUSTION REACTION)

Explanation:

I hope this helps :)

You might be interested in
PLEASE HELP!!
sp2606 [1]
Inbox me for the answer

6 0
3 years ago
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?
Westkost [7]
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



6 0
3 years ago
I need please fast ASAP
sdas [7]
Kindly checkout the attached pic. It contains all your required questions. 

4 0
3 years ago
Most atoms have no net charge because they have
Ne4ueva [31]

Atoms have no electric charge because the protons and electrons "cancel out" each others charges. Neutrons have no charge. What is the atomic number of an element? The atomic number is the number of protons in the atom's nucleus.

Hope this helps have a great day :)

6 0
3 years ago
Read 2 more answers
Other questions:
  • In a coffee-cup calorimeter, 50.0ml of 0.100M AgNO3 and50.0ml of 0.100M HCl are mixed to yield the following reaction:
    13·1 answer
  • PLEASE HELP why does the atomic radius of elements increases when you go down the Periodic Table
    6·1 answer
  • Convert the following to Celsius
    7·1 answer
  • A compound or material formed by a chemical reaction is known as the of that reaction.
    6·1 answer
  • the density of air at ordinary atmospheric pressure and 25 degrees celcius is 1.19 g/L. what is the mass, in kilograms, of the a
    5·1 answer
  • Suppose you need to built a raft to cross a fast-moving river. Describe the physical and chemical properties of that raft that w
    9·1 answer
  • Which types of reactions are also redox reactions?
    14·2 answers
  • A 0.0200 M NaCl solution was formed when 38.0 grams of NaCl was dissolved in
    13·1 answer
  • 7. Which of these is not matter?<br> a. a cloud<br> c. sunshine<br> b. your hair<br> d. the sun
    15·1 answer
  • Acids which contain only hydrogen and a single other element are referred to as.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!