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My name is Ann [436]
4 years ago
14

An objects volume can be found by adding its mass by its?

Chemistry
1 answer:
Inessa05 [86]4 years ago
4 0
Volume* density=MASS
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Pt 2. Chem Reactions 50 PTS
Dahasolnce [82]

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called a limiting reagent.

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.

A product is a substance that is present at the end of a chemical reaction.

Hence,

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

6 0
2 years ago
Copy and complete the following concept map on chemical Reactions
ExtremeBDS [4]
Can you attach the following concept map on chemical reactions?
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3 years ago
Which of the following best describes technology
kotegsom [21]

were are the choices

5 0
3 years ago
Read 2 more answers
What must be part of a quantitative observation?
Likurg_2 [28]

Quantitative observations include numerical data. Ex: 32 degrees, 10 inches, etc.

4 0
3 years ago
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In the spring of 1984, concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecul
Lady bird [3.3K]

869.6 × 10¹⁴ molecules of EDB

Explanation:

We have 1.9 lb of flour with a EDB concentration of 31.5 ppb.

We need to transform lb in grams.

1 lb = 453.6 grams

1.9 lb = (1.9 × 453.6) / 1 = 861.8 grams

Now we determine the number of molecules of EDB in the sample by devise the following reasoning:

if we have        31.5 × 10⁻⁹ g of EDB in 1 g of sample

then we have   X  g of EDB in 861.8 g of sample

X = (31.5 × 10⁻⁹ × 861.8) / 1 = 27146.7 × 10⁻⁹ g of EDB

Molecular mass of EDB (C₂H₄Br₂) = 188 g/mole

Taking in account that 1 mole of any substance contains 6.022 × 10²³ (Avogadro’s number) molecules we devise the following reasoning:

if       188 g of EDB contains 6.022 × 10²³ molecules

then 27146.7 × 10⁻⁹ g of EDB contains Y molecules

Y = (27146.7 × 10⁻⁹ × 6.022 × 10²³) / 188 = 869.6 × 10¹⁴ molecules of EDB

Learn more:

about Avogadro’s number

brainly.com/question/1445383

#learnwithBrainly

8 0
4 years ago
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