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lina2011 [118]
3 years ago
12

How to calculate atomic mass?​

Chemistry
2 answers:
Sati [7]3 years ago
8 0

Explanation:

start by finding the atomic number of the element which is the number above the element on the perodic table . Next , find the number of neutrons in the nucleus by subtracting the atomic number from the istope number . Finally , add the atomic number of neutrons to get the atomic mass.

Alexus [3.1K]3 years ago
7 0
To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.

Hope this helps :)
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When the population of organisms in an ecosystem is in balance, we consider the ecosystem to be: A. The ecosystem is in successi
krek1111 [17]
The answer is B. Equilibrium means a state in which opposing forces or influences are balanced.
7 0
3 years ago
Four people weigh a standard mass of 10.00g on the same balance. Which of the following sets of readings suggests measurements t
Svetach [21]
An example of accurate but not precise would be 3 people weigh a 10g sample. the weights are 0g, 10g, & 20 grams. the scale is way off but the weights average to the right thing.
precise but not accurate would weighing a 10g sample 3 times and getting 5.5, 5.4, & 5.5. they'e all incredibly similar therefore precise but its nowhere near 10, so not accurate. 
neither precise nor accurate would be 3 weights being 10, 20, &30. It averages wrong and is imprecise.
5 0
3 years ago
In which of the following compounds does the carbonyl stretch in the IR spectrum occur at the lowest wavenumber?
klio [65]

Answer:

a. Cyclohexanone

Explanation:

The principle of IR technique is based on the <u>vibration of the bonds</u> by using the energy that is in this region of the electromagnetic spectrum. For each bond, there is <em>a specific energy that generates a specific vibration</em>. In this case, you want to study the vibration that is given in the carbonyl group C=O. Which is located around 1700 cm-1.

Now, we must remember that the <u>lower the wavenumber we will have less energy</u>. So, what we should look for in these molecules, is a carbonyl group in which less energy is needed to vibrate since we look for the molecule with a smaller wavenumber.

If we look at the structure of all the molecules we will find that in the last three we have <u>heteroatoms</u> (atoms different to carbon I hydrogen) on the right side of the carbonyl group. These atoms allow the production of <u>resonance structures</u> which makes the molecule more stable. If the molecule is more stable we will need more energy to make it vibrate and therefore greater wavenumbers.

The molecule that fulfills this condition is the <u>cyclohexanone.</u>

See figure 1

I hope it helps!

4 0
3 years ago
The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
Kay [80]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

6 0
3 years ago
The compound gallium phosphide () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities f
9966 [12]

Answer:

0.08875

Explanation:

Hello,

In this case, the first step is to compute the difference in the electronegativity for the formed bond between gallium and phosphorous by:

\Delta E=2.1-1.6\\\\\Delta E=0.5

Thus, we can compute the percentage of ionic character by:

\%\  ionic\ character=16\Delta E +3.5 (\Delta E)^2\\\\\%\  ionic\ character=16*0.5+3.5*0.5^2\\\\\%\  ionic\ character=8.875\%

So the fraction is just:

\frac{8.875}{100}=0.08875

Which has sense since gallium phosphide is a non-polar compound.

Regards.

3 0
3 years ago
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