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3 years ago

Solve the equation. X^2=2x^2 + 4

Mathematics

2 answers:

Ierofanga [76]3 years ago

8 0

Answer:

No real solution or if you learned imaginary numbers, 2i

Step-by-step explanation:

x^2=2x^2+4

x^2=x^2+x^2+4

Subtract x^2 from both sides

0=x^2 + 4

Subtract 4 from both sides

x^2 = -4

Square root both sides

x=sqrt(-4)

x=2i or no real solutions

icang [17]3 years ago

8 0

First step:
Subtract 2x^2 from both sides to get x by itself but remember there is always an invisible 1 infront of x, So...

1x^2 = 2x^2 + 4
-2x^2 -2x^2

-1x^2 = 4

Second step:
Divide -1 from both sides to get x by itself

-1 / -1 x^2 = 4 / -1

X^2 = -4

Third step:
Since the x has an exponent, the power function with an even exponent is always positive or 0

X = 0

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Line BC has an equation of a line Y equals 2X +3 and F has an equation of a line Y equals -1/2 x+4 these two equations represent

Masja [62]

Answer:

Lines BC and F represent perpendicular lines

Step-by-step explanation:

we have

Line BC

$y=2x+3$

the slope of the line BC is $m=2$

Line F

$y=-(1/2)x+4$

the slope of the line F is $m=-1/2$

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

$m1*m2=-1$

we have

$m1=2$ -----> slope line BC

$m2=-1/2$ -----> slope line F

Find the product of their slopes

$(2)(-1/2)=-1$

therefore

Lines BC and F represent perpendicular lines

6 0

3 years ago

A regular hexagon has an area of 750.8 cm. The side length is 17 cm. Find the apothem.

kompoz [17]

Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.

We have to find the apothem of the regular hexagon.

The formula for determining the apothem of regular hexagon is $s \div {{2 \tan (\frac{180}{n})}$ , where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.