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2 years ago

A regular hexagon has an area of 750.8 cm. The side length is 17 cm. Find the apothem.

Mathematics

1 answer:

kompoz [17]2 years ago

5 0

Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.

We have to find the apothem of the regular hexagon.

The formula for determining the apothem of regular hexagon is $s \div {{2 \tan (\frac{180}{n})}$ , where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.

So, apothem = $17 \div {2 tan(\frac{180}{6})$

= $17 \div {2 tan(30)$

= $17 \div {1.15}$

= 14.78 units

Therefore, the measure of apothem of the regular hexagon is 14.7 units.

Option B is the correct answer.

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Elden [556K]

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2 years ago

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12 is 90% of what number?<br><br><br> with steps

a_sh-v [17]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here 12 is 90% of a number.
So we can say that 90% of That number is 12 .
In this way we can get the the number

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Let,

the number=x

<h3>According to the question ,</h3>

${:}\longrightarrow$ $\sf 90\% \:of \;x=12$

We know 90%=90/100
so add it

${:}\longrightarrow$ $\sf {\dfrac {90}{100}}\times x=12$

${:}\longrightarrow$ $\sf {\dfrac {90x}{100}}=12$

Now use cross multiplication method

${:}\longrightarrow$ $\sf 90x=12\times 100$

${:}\longrightarrow$ $\sf 90x=1200$

Now interchange sides .

${:}\longrightarrow$ $\sf x={\dfrac {1200}{90}}$

${:}\longrightarrow$ $\sf x={\dfrac {200}{15}}$

Answer will come in decimals so we take approximate value.

${:}\longrightarrow$ $\sf x=13.3$

${:}\longrightarrow$ $\sf x=approximately \:13$

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2 years ago

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Step-by-step explanation:

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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

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2 years ago

In the book 365 Penguins, the family received a new penguin each day. They received their first penguin on January 1st and this

Eddi Din [679]

Answer:

181 penguins on the last day of June.

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Step-by-step explanation:

We have been given that in the book 365 Penguins, the family received a new penguin each day. They received their first penguin on January 1st and this pattern continued throughout this non-leap year.

First of all we need to find number of days in January to June.

January has 31 days, February has 28 days (Not a leap year), March has 31 days, April has 30 days, May has 31 days and June has 30 days.

$\text{Days from January to June}=31+28+31+30+31+30$

$\text{Days from January to June}=181$

Since penguin family receives 1 penguin each day, so 181 penguins will be in 181 days.

Therefore, the penguin family will have 181 penguins on the last day of June.

Now, we need to find the day, which will be on 250th day.

We already know that 181st day would be 30th June.

We know that July and August each has 31 days, so we will add 62 days to 181 that is $181+62=243$ .

243rd day would be 31st August.

Now, we will add 7 days to 243 days to get 250th day.

Since next month to August is September, therefore, the family will receive 250th penguin on 7 September.

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