10.5 hours
let t be time then distance travelled by both is
Mr Burges ⇔ d = 50t ( distance = speed × time )
Mrs Burges ⇒ d = 70(t - 3)
At the point of overtaking both will have travelled the same distance
equating their distance and solving for t
70(t - 3) = 50t
70t - 210 = 50t ( subtract 50t from both sides )
20t - 210 = 0 ( add 210 to both sides )
20t = 210 ( divide both sides by 20 )
t = 10.5 hours
Second side= x
First side = 2x
Third side = x+5
x+2x+x+5=49
4x=44
x=11
1st side= 22
2nd side = 11
3rd side = 16
Answer:
Janice and Karen could do in 1 day:
Step-by-step explanation:
To identify how much of the job could janice and caren do in 1 day, first, we must find how much of the job make just 1 person at the same rate:
If three persons make a job in 3 1/3 days, 1 person make the job in x:
- 3 persons ⇒ 3 1/3 days or 10/3 days
- 1 person ⇒ x
Then:
(we cancel the unit "persons")
- x = 10 days
Just a person would need 10 days to complete a job, now, we're gonna divide this value in 2 to obtain the time that need two persons to complete a job:
- Time to complete a job between 2 persons =

- Time to complete a job between 2 persons = 5 days
How two persons need 5 days to complete a job (in this case, the two persons are Janice and Karen), we can make a simple rule of three to obtain the percentage made in 1 day:
- 5 days ⇒ 100% of a job
- 1 day ⇒ x
Then:
(you can use the % if you want, the result is the same)

As you can see, <u><em>Janice and Karen just in a day could do 20% of the job</em></u>.
Answer:
x=4
y=1
Step-by-step explanation:
4x=7y+9
4x+y=17
7y+9+y=17
8y=17-9
8y=8
y=1
so
4x=7*1+9
4x=16
x=16/4
x=4