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2 years ago

Help please I’ll mark you

Mathematics

1 answer:

kumpel [21]2 years ago

5 0

Answer:

Step-by-step explanation:

If you already have an angle of 148 on the arc TU, then 180-148=32

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If 2x+3y = 4 and y = 34, what is the value of x?

weeeeeb [17]

Answer:

Step-by-step explanation:

2x + 3y = 4

When y = 34

2x + 3(34) = 4

2x + 102 = 4

2x = 4 - 102

2x = - 98

x = -98/2

x = - 49

4 0

2 years ago

A car rental costs a fee of $150 plus $35 per

lutik1710 [3]

Answer:

5 hours

Step-by-step explanation:

We know that Joey spent a total of $325. He first paid the fee of $150. Let's subtract $150 from $325.

$325 - $150 = $175

Now, we know that it costs $35 per hour to rent the car. So, we divide $175 by $35 to find out how many hours Joey rented the car for.

$175 ÷ $35 = 5 hours

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2 years ago

(6 x2 - 6x + 4) - (x2 – 5x – 9)

DedPeter [7]

The answer is 9x+13

4 0

3 years ago

PLZZ HELP ME

dimulka [17.4K]

Answer:

125/100 X 105 = 131.25

loan total = $131.25

3 0

2 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$