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2 years ago

Solve by using the perfect squares method. x2 + 4x + 4 = 0 a. 2 b. –2 c. 4 d. –4

2 answers:

7 0

Solve your equation step-by-step.

x2+4x+4=0

Factor left side of equation.

(x+2)(x+2)=0

Set factors equal to 0.

x+2=0

or

x+2=0

x=−2

Stels [109]2 years ago

5 0

$a^2+2ab+b^2=(a+b)^2 \\ \Downarrow \\
x^2+4x+4=x^2 + 2 \times 2 \times x +2^2=(x+2)^2 \\ \\
x^2+4x+4=0 \\
(x+2)^2=0 \\
x+2=0 \\
x=-2$

The answer is B.

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