Please solve this problem and I’ll give brainliest
1 answer:
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Answer:
E-F and E-D
C-B and C-D
Step-by-step explanation:
The circle and triangle are as shown. The options are:
- A-B and C-B
- E-F and E-D
- E-D and C-D
- A-F and E-F
- C-B and C-D
By drawing radius lines from the center of the circle to the tangent points B, D, and F, we can divide the triangle into 3 kites. Therefore, only segments that are legs of the same kite are congruent. So the answer must be E-F and E-D, and C-B and C-D.
Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
