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Irina-Kira [14]
3 years ago
6

(PLEASE HELP!) (IM GIVING GOOD POINTS!)

Mathematics
2 answers:
Nostrana [21]3 years ago
8 0

Answer:

No, he incorrectly rounded 1.25 to 2

Step-by-step explanation:

To find out how many pages Yutto writes in 1 hour we divide

1.25/2=0.625

Now we multiply

0.625×6=3.75

3.75≠6

So now we know that Yutto was incorrect so we can eliminate the last two options. Now how did he get his original estimate? For option A,

1.25 is rounded to 2

2/2=1

1×6=6

So the answer is A

morpeh [17]3 years ago
7 0

Answer:

No, he incorrectly rounded 1.25 to 2

Step-by-step explanation:

hope this helps :)

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A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a​ single-strand electric
allochka39001 [22]
I'm fairly certain that using that wire you can have the same area no matter what dimensions there are, but if you do the square root, or \sqrt{} of 19,001,900 then you get 4359.11688. So your dimensions are 4359.11688 x 4359.11688. To get area, do length x width to get <span>1.9*1 0^{7}.

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4 0
3 years ago
Write an exponential function in the form y=ab^x that goes through points (0,7) and (5,1701).
Marizza181 [45]

Answer:

y = 7 3^{x}

Step-by-step explanation:

Use the given ordered pairs to find a and b

Using (0, 7 ), then

7 = a b^{0} ( b^{0} = 1 ), thus

a = 7

y = 7 b^{x}

Using (5, 1701 )

1701 = 7 b^{5} ( divide both sides by 7 )

243 = b^{5} ( take the fifth root of both sides )

b = \sqrt[5]{243} = 3 , thus

y = 7 3^{x}

3 0
3 years ago
George wishes to increase the percent of acid in 50 ml of a 15% acid solution in water
PtichkaEL [24]

Answer:

screw this question

Step-by-step explanation:

To change from 15% to 25% he needs to add 10%.

If the solution is 50ml then he needs to add 10% which is 5ml... But if he adds 5 ml then the solution will be 55ml total, so that doesn't make sense. He has to take some of the solution that's not acid before adding the 5ml...

3 0
3 years ago
Read 2 more answers
If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?
Andreas93 [3]

Until now, given a function  f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given  f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and  

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.  

 

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of  exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find  f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0
3 years ago
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96743 divided by 25 im at school in person so uh ya lol
mash [69]

Answer:

3,869.72

Step-by-step explanation:

5 0
3 years ago
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