Answer:
98.12 m
Explanation:
Initial speed(v) = 25.0 m/s
Coefficient of static friction (u) = 0.650
The minimum value of the coefficient of kinetic friction should be the coefficient of static friction.
Kinetic friction is given as
umg = ma (a is the required acceleration)
We then have
a = -ug
= -(0.65*9.8)
= -6.37 m/s^2
The shortest distance d is obtained by
d = (V^2 - v^2)/ 2a
V = 0 m/s (final velocity)
d = (0 - 25^2) / 2(-6.37)
d = -625/-6.37
d = 98.12 m
Answer:
55.6 nC
Explanation:
The electric field at the surface of a charged sphere has the same expression of the electric field produced by a single point charge located at the centre of the sphere and having the same charge of the sphere, so it is given by

where
is the Coulomb's constant
Q is the charge on the sphere
r is the radius of the sphere
In this problem we know
E = 890 N/C is the magnitude of the electric field on the sphere
r = 0.750 m is the radius of the sphere
So by re-arranging the equation we can find the net charge on the sphere:

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