Question

A flask that can withstand an internal pressure of 2500 torr, but no more, is filled with a gas at 21.0C and 758 torr and heated. At what temperature will it burst?

Answer 1

Answer : The temperature will be, 969.66 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 758 torr

$P_2$ = final pressure of gas = 2500 torr

$T_1$ = initial temperature of gas = $21.0^oC=273+21.0=294K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{758torr}{294K}=\frac{2500torr}{T_2}$

$T_2=969.66K$

Thus, the temperature will be 969.66 K