$4x^2-35x+4\\\\a=4;\ b=-35;\ c=4\\\\\Delta=b^2-4ac\to\Delta=(-35)^2-4\cdot4\cdot4=1225-64=1161\\\\x=\frac{-b\pm\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1161}=\sqrt{9\cdot129}=3\sqrt{129}\\\\x=\frac{-(-35)\pm3\sqrt{129}}{2\cdot4}=\frac{35\pm3\sqrt{129}}{8}\\\\4x^2-35x+4=4\left(x-\frac{35-3\sqrt{129}}{8}\right)\left(x-\frac{35+3\sqrt{129}}{8}\right)$

8 0

3 years ago

Need help with b, picture attached.

Vikki [24]

$7500/75=100$
This means that a field of those dimensions would not be the required length of a minimum of 110 feet.

7 0

3 years ago

Lines a and bare parallel 79 What is the measure of angle b? Enter your answer in the box b=

Len [333]

If lines a and b are parallel, then aº = 79º = dº = bº.

6 0

3 years ago