I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is ![f(x) = \frac{4}{x}, \ \ g(x) = x^2+9](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B4%7D%7Bx%7D%2C%20%20%5C%20%5C%20g%28x%29%20%3D%20x%5E2%2B9)
Another possible answer is ![f(x) = \frac{4}{x+9}, \ \ g(x) = x^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B4%7D%7Bx%2B9%7D%2C%20%5C%20%5C%20g%28x%29%20%3D%20x%5E2)
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have
![f(x) = \frac{4}{x}\\\\f( g(x) ) = \frac{4}{g(x)}\\\\f( g(x) ) = \frac{4}{x^2+9}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B4%7D%7Bx%7D%5C%5C%5C%5Cf%28%20g%28x%29%20%29%20%3D%20%5Cfrac%7B4%7D%7Bg%28x%29%7D%5C%5C%5C%5Cf%28%20g%28x%29%20%29%20%3D%20%5Cfrac%7B4%7D%7Bx%5E2%2B9%7D)
In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)
Answer:
3
Step-by-step explanation:
The assumed frequency of defects is 2/16.
When we apply this rate to 24, (2/16)*24, we get 3.
Therefore, we can assume around 3 defective boxes tomorrow.
Answer:
Step-by-step explanation:
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Answer:
b
Step-by-step explanation: