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boyakko [2]
2 years ago
10

Which statement about spontaneous and nonspontaneous processes is correct? Spontaneous processes are favored by a decrease in De

lta. H, but nonspontaneous reactions are favored by an increase in Delta. H. Spontaneous processes are favored by a decrease in Delta. S, but nonspontaneous reactions are favored by an increase in Delta. S. An increase in Delta. S favors both spontaneous and nonspontaneous processes. A decrease in Delta. H favors both spontaneous and nonspontaneous processes.
Chemistry
1 answer:
cupoosta [38]2 years ago
6 0

The statement correct for the processes are spontaneous reaction have negative Delta H and non-spontaneous reaction has positive Delta H. Hence, option A is correct.

The value of Delta H in the reaction is the change in enthalpy of the reaction. The enthalpy of the reaction determines the reaction to be spontaneous or non-spontaneous.

<h3>What determines spontaneous and non-spontaneous reaction?</h3>

The spontaneous reaction is required with the energy input for the reaction to proceed. The energy is required by the system thus, the value of Delta H is negative.

The non-spontaneous reaction requires with the loss of energy in the formation of the product. The energy released gives the values of Delta H positive.

Thus, the statement correct for the processes are spontaneous reaction have negative Delta H and non-spontaneous reaction has positive Delta H. Hence, option A is correct.

Learn more about Delta H, here:

brainly.com/question/10601562

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Explanation:

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2 years ago
Calculate the value of ka for acetylsalicylic acid
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The value of Ka for acetylsalicylic acid will be calculated as Ka=(x+a)²/x.

<h3>What is Ka?</h3>

Ka is known by the name of acid dissociation constant and for weak acid HA at equilibrium Ka will be calculated as:

Ka = [H⁺][A⁻] / [HA]

Chemical equation with ICE table for the acetylsalicylic acid will be shown as:

                  C₉H₈O₄(aq)  +  H₂O(l)  ⇄  C₉H₇O₄(aq)  +  H₃O⁺(aq)

Initial:                 x                                        0                     0

Change:            -a                                        +a                   +a

Equilibrium:      x-a                                      x+a                 x+a

So, Ka for acetylsalicylic acid will be calculated by putting values on the above equation as:

Ka = [x+a][x+a] / [x-a]

Value of a is negligible as compared to the value of x of acetylsalicylic acid so the term x-a becomes x and equation will be written as:

Ka = (x+a)² / x

By knowing the all values of concentration we can calculate the value of Ka.

Hence Ka value for acetylsalicylic acid will be calculated by using the formula as Ka = (x+a)² / x.

To know more about Ka, visit the below link:

brainly.com/question/26998

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