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Anna007 [38]
3 years ago
10

Assuming 80 mg of vitamin c present 29.57 ml if oj how many milliliters of 0

Chemistry
1 answer:
BigorU [14]3 years ago
5 0
I think you add 29.57 + 80 and the answer would be 30.37
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How is a mole related to concentration?
DIA [1.3K]

Answer:

Explanation:

You multiply the concentration (in moles per litre) by the volume in litres. The number of moles of a substance in one litre of solution is called its molarity. The official symbol for molarity is “c” (concentration), but most people use the symbol “M”. where n is the number of moles and V is the volume in litres

7 0
3 years ago
Given:
marusya05 [52]

Answer:

92.6 g.

Explanation:

  • The balanced equation is:

CaC₂ + N₂ → CaCN₂ + C.

  • It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
  • We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:

n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.

  • We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.

∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.

<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>

  • Now, we can get the grams of N₂  consumed to produce 265.0 g of CaCN₂:

∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.

7 0
4 years ago
Identify the intermediate in the halogenation of alkanes.a) Anionb) Cationc) Radicald) Dimer
Alex_Xolod [135]

Answer: Option C - Radical

Explanation:

A radical is a chemical specie carrying a lone electron. In the halogenation of alkanes: take Methane CH4 as the alkane, and Chlorine Cl as the halogen.

The step by step halogenation process is as follows:

CH4 + Cl2 --> CH3• + HCl + Cl•

CH3• + Cl2 --> CH3Cl + HCl

CH3Cl + Cl2 --> CH2Cl2 + HCl + Cl•

CH2Cl2 + Cl2 --> CHCl3 + HCl

CHCl3 + Cl2 --> CCl4 + HCl + Cl•

Chlorine molecule attack methane knocking off an hydrogen atom from it and forming a methyl radical (CH3•), that is subsequently attack by another chlorine molecule. This cycle repeats itself, until no hydrogen atom is available for substitution by the highly reactive chlorine radical.

Note: no cation or anion is formed in the halogenation process

3 0
3 years ago
What is the nuclear binding energy in joules for an atom of helium–4? Assume the following: Mass defect = 5.0531 × 10-29 kilogra
almond37 [142]
The mass defect refers to the amount of mass that has been converted to energy to hold the nucleus together. That means the mass defect is what you're using in your equation to calculate E. <span>E=m<span>c2</span></span><span>E=(5.0531×<span>10<span>−29</span></span>)(3×<span>108</span><span>)2</span></span><span>E=4.55×<span>10<span>−12</span></span></span><span> The binding energy is 4.55 x 10^(-12) J. Let me know if you have any questions!</span>
3 0
3 years ago
Read 2 more answers
Help this mirrorball, please​
grin007 [14]

Answer:

Option B

Explanation:

Avagadro's hypothesis showed that at constant temperature and pressure equal volume of all gases contains equal no of molecules.

Avagadro's constant is known as 6.022×10^23

5 0
3 years ago
Read 2 more answers
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