Question

in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this compound

Answer 1

Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

Further explanation

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

$\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5$

mol of element G :

$\tt mol=\dfrac{4}{16}=0.25$

mol ratio A : G = 0.5 : 0.25 = 2 : 1