in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
1 answer:
Additional information
Relative atomic mass(Ar) : A=7, G=16
The empirical formula : A₂G
<h3>Further explanation</h3>Given
3.5g of element A
4.0g of element G
Required
the empirical formula for this compound
Solution
The empirical formula is the smallest comparison of atoms of compound forming elements.
The empirical formula also shows the simplest mole ratio of the constituent elements of the compound
mol of element A :
mol of element G :
mol ratio A : G = 0.5 : 0.25 = 2 : 1
You might be interested in
Answer:
Its pressure will be 0.54 atm at 100 K.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
Gay-Lussac's law can be expressed mathematically as the quotient between pressure and temperature equal to a constant:
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
In this case:
- P1= 1.75 atm
- T1= 50 °C= 323 K (being 0 C=273 K)
- P2= ?
- T2= 100 K
Replacing:
Solving:
P2= 0.54 atm
<u><em>Its pressure will be 0.54 atm at 100 K.</em></u>
Answer: 125 g
Explanation:
To calculate the moles :
The balanced reaction is:
According to stoichiometry :
1 mole of require = 3 moles of
Thus 1.30 moles of will require=
of
Mass of
Thus 125 g of will be needed to burn 36.1 g of
Answer:
n = 1.24 moles
Explanation:
Given that,
Mass = 153 grams
Molar mass of KClO₃ = 122.55 g/mol
We need to find the number of moles.
We know that,
No. of moles = given mass/molar mass
So,
So, there are 1.24 moles in 153 g of KClO₃.