Answer:
Balanced
Explanation:
Please help me by marking me brainliest. I'm one away :)
Answer:
Explanation:
Given parameters:
Concentration of H₃O⁺ = 5.6 x 10⁻²M
Solution:
To solve for the concentration of H₃O⁺ in the solution, we simply use the expression below:
pH = -log₁₀[H₃O⁺]
where [H₃O⁺] = 5.6 x 10⁻²M is the concentration of H₃O⁺
pH = -log₁₀[5.6 x 10⁻²] = - x -1.25 = 1.25
Answer:
pH= 11.5
Explanation:
To the calculation of the <u>pH value</u>, we need to write the ionization equation first. Then using the <u>ICE table</u> and the information given by the problem we can set up the problem:
I 1.1 M Zero Zero
C -X +X +X
E 1.1-X X X
As next step, using the <u>equilibrium expression</u> for Kb we can replace the terms find in the ICE table and then <u>solve for X</u>, so:
![Kb=\frac{[C_4H_4N_2O_3NH_3^+][OH^-]}{[C_4H_4N_3O_3NH_2]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BC_4H_4N_2O_3NH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BC_4H_4N_3O_3NH_2%5D%7D)
![9.2x10^-^6=\frac{[X][X]}{[1.1-X]}](https://tex.z-dn.net/?f=9.2x10%5E-%5E6%3D%5Cfrac%7B%5BX%5D%5BX%5D%7D%7B%5B1.1-X%5D%7D)
![(9.2x10^-^6)*[1.1-X]=X^2](https://tex.z-dn.net/?f=%289.2x10%5E-%5E6%29%2A%5B1.1-X%5D%3DX%5E2)
With the value of X we can find the <u>pOH</u> (lets remember that X<u> is the concentration of OH-</u>), so:
Finally, we can find the <u>pH value</u> with the equation:
<u>The 1.1 M allantoin solution have a pH value of 11.5</u>
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
