Answer:
Below
Explanation:
2) there are 28 protons in this isotope
The number that is on the bottom of the "stacked pair" tells you how many protons are in this isotope. It is often represented by the variable Z.
3) there are 35 neutrons in this isotope
Subtract the number of protons (28) from the top number
4) there are 28 electrons in the neutral element of Nickel
If you were to look at the period table and find Ni, you would see that its atomic number is 28. This number tells us the amount of protons and electrons there are in that element.
5) 62.9296694 atomic mass units
Just search it up (unless your teacher wants you to calculate it)
6) there are 92 protons in this isotope
Again just look at the Z value to find the proton count
7) there are 146 neutrons in this isotope
Subtract 238 - 92 = 146
8) there are 92 electrons in the neutral element of uranium
Again just look at the periodic table and find U
9) 238.0507882 atomic mass units
10) 12C or carbon 12 is more likely to bond with oxygen that 14c carbon 14
This is because 12C is more abundant at 98.93% than 14C
Hope this helps! Best of luck <3
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as
pH = pKa + log [A]/[HA]
where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid
Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol
Solution:
pKa = - log ( 1.8x10^-5) = 4.74
[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles
pH = 4.74 + log (.115/0.085)
pH = 4.87
Answer:
It takes 1.32x10⁻⁷s for the concentration of A to fall by a factor of 8
Explanation:
The equation that represents a first-order kinetics is:
Ln ([A] / [A]₀] = -kt
<em>Where [A] is actual concentration, [A]₀ is initial concentration, K is rate constant (For the given problem, 1.57x10⁷s⁻¹ and t is time.</em>
<em />
As you want the time when you have [A] in a factor of 8 = [A] / [A]₀ = 1/8
Replacing:
Ln ([A] / [A]₀] = -kt
Ln (1/8) = -1.57x10⁷s⁻¹*t
t = 1.32x10⁻⁷s
<h3>It takes 1.32x10⁻⁷s for the concentration of A to fall by a factor of 8</h3>
<u>Answer:</u> The atomic weight of the second isotope is 64.81 amu.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of atomic masses of each isotope each multiplied by their natural fractional abundance
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
Let the mass of isotope 2 be 'x'
Mass of isotope 1 = 62.9 amu
Percentage abundance of isotope 1 = 69.1 %
Fractional abundance of isotope 1 = 0.691
Mass of isotope 2 = 'x'
Percentage abundance of isotope 2 = 30.9%
Fractional abundance of isotope 2 = 0.309
Average atomic mass of copper = 63.5 amu
Putting values in equation 1, we get:
![\text{Average atomic mass of copper}=[(62.9\times 0.691)+(x\times 0.309)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20copper%7D%3D%5B%2862.9%5Ctimes%200.691%29%2B%28x%5Ctimes%200.309%29%5D)

Hence, the atomic weight of second isotope will be 64.81 amu.
The correct choice in the options above is the aerosols. It is because the aerosols are the ones that are combined with gaseous substances and water in order for it to be formed. Without the gaseous substance being joined with the water then the aerosols won't be produced.