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2 years ago

I need help really bad please

Mathematics

1 answer:

yuradex [85]2 years ago

3 0

Answer:

$9$

Step-by-step explanation:

$72 = 2^3 \cdot \boxed{3^2}$

$27 = 3 \cdot \boxed{3^2}$

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3 years ago

If i only had 2819 in my account and i now have 3349 how much more deposited?

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Step-by-step explanation:

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4 years ago

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Step-by-step explanation:

8 0

3 years ago

QUESTION 1

SVEN [57.7K]

Answer:

1st Error: In going from Step 3 to Step 3.

Reason: Negative sign is not distributed inside the brackets.

2nd Error: In going from Step 5 to Step 6

Reason: Sign of the number is not changed while moving to other side of inequality,

a) 12=-4(-6x-3) and x+5=-5x+5

b) -(7-4x)=9 and 5x+34=-2(1-7x) and -8=-(x+4)

Step-by-step explanation:

Question 1)

The given inequality is:

$\frac{5}{12}-\frac{x-3}{6} \leq \frac{x-2}{3}$

Step 1: Making the denominators common for all fractions

$\frac{5}{12}-\frac{2}{2} \times \frac{x-3}{6} \leq \frac{4}{4} \times \frac{x-2}{3}$

This step is done correctly in the given solution.

Step 2: Simplifying

$\frac{5}{12}-\frac{2x-6}{12}\leq \frac{4x-8}{12}$

This step is done correctly in the given solution

Step 3: Multiplying both sides by 12, and simplifying.

$5-(2x-6)\leq 4x-8\\\\ 5-2x+6\leq 4x-8$

First error is made in this step. While opening the brackets, the negative sign should be distributed inside the bracket, which will change the signs.

Step 4: Simplification:

$11-2x\leq 4x-8$

Step 5: Moving Common terms to one side and simplifying

$-2x-4x\leq -8-11\\\\ -6x\leq -19$

Error was made in this step. When a number is moved to other side, its sign will be changed.

Step 6: Dividing both sides by -6

$x\geq \frac{19}{6}$

Conclusion:

1st Error: In going from Step 3 to Step 3.

Reason: Negative sign is not distributed inside the brackets.

2nd Error: In going from Step 5 to Step 6

Reason: Sign of the number is not changed while moving to other side of inequality,

Question 2:

In the Equation 2: 12=-4(-6x-3), when -4 will be multiplied inside the brackets, the 12 on eft hand side will cancel the 12 that will appear on right hand side, giving a result that will lead to x = 0.

Same is the case with Equation 6: x+5=-5x+5, 5 on both sides will cancel out leaving x = 0.

So, 2nd and 6th equations will have the same solution.

In Equation 1, on expanding the bracket and moving 7 to other side, we get a relation: 4x = 16

In Equation 3, on simplifying the right hand side, and carrying common terms to one side, we get the relation: - 9x = -36

In Equation 5, on expanding the bracket and simplifying the relation is reduced to 4 = x

It can be observed that all these 3 equations have the same solution i.e. x = 4

So, the following set of Equations have the same solution:

a) 12=-4(-6x-3) and x+5=-5x+5

b) -(7-4x)=9 and 5x+34=-2(1-7x) and -8=-(x+4)

6 0

3 years ago

Read 2 more answers