Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6
Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.
Probability of selecting a basketball card = 6/10 = 0.6
Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated.
Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
Answer:
The rational function that is graphed is B
Answer:converge at ![I=\frac{1}{3}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
Given
Improper Integral I is given as
![I=\int^{\infty}_{3}\frac{1}{x^2}dx](https://tex.z-dn.net/?f=I%3D%5Cint%5E%7B%5Cinfty%7D_%7B3%7D%5Cfrac%7B1%7D%7Bx%5E2%7Ddx)
integration of
is -![\frac{1}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D)
![I=\left [ -\frac{1}{x}\right ]^{\infty}_3](https://tex.z-dn.net/?f=I%3D%5Cleft%20%5B%20-%5Cfrac%7B1%7D%7Bx%7D%5Cright%20%5D%5E%7B%5Cinfty%7D_3)
substituting value
![I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]](https://tex.z-dn.net/?f=I%3D-%5Cleft%20%5B%20%5Cfrac%7B1%7D%7B%5Cinfty%20%7D-%5Cfrac%7B1%7D%7B3%7D%5Cright%20%5D)
![I=-\left [ 0-\frac{1}{3}\right ]](https://tex.z-dn.net/?f=I%3D-%5Cleft%20%5B%200-%5Cfrac%7B1%7D%7B3%7D%5Cright%20%5D)
![I=\frac{1}{3}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B3%7D)
so the value of integral converges at ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
The answer is 8 it should be