Question

A line passes through the point (-9,-4) and has a slope of -2/3 . write an equation in slope intercept form for this line

Answer 1

Answer:

$y=-0.667x+-10$

Step-by-step explanation:

Given the following question:

Point A = (-9, -4), (x1, y1)
Point B = (-6, -6), (x2, y2)

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{-6--4}{-6--9} =\frac{-2}{3}$
$m=\frac{-2}{3}$

Write in slope intercept form:

$y=mx+b$
$m=\frac{-2}{3}=-2\div3=-0.667$
$y=-4$
$x=-9$
$-4=-0.667\times-9+b$
$-0.667\times-9=6$
$b=-10$
$y=-0.667x+-10$

Hope this helps.