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3 years ago

Solve the equation: 4 1/5 + b = 9 3/5

2 answers:

7 0

$4 \frac{1}{5}+ b = 9 \frac{3}{5} \ \ | (-4\frac{1}{5})\\ \\4 \frac{1}{5 }-4 \frac{1}{5}+ b = 9 \frac{3}{5}-4 \frac{1}{5}\\ \\b= 5\frac{2}{5}=5.4$

kvasek [131]3 years ago

3 0

$4 \frac{1}{5} + b = 9 \frac{3}{5} \\\\b= 9 \frac{3}{5}-4 \frac{1}{5} \\\\b=5 \frac{2}{5}$

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Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

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So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

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Step-by-step explanation:

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