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Cloud [144]
3 years ago
10

Solve the equation:  4 1/5 + b = 9 3/5

Mathematics
2 answers:
Yanka [14]3 years ago
7 0
4 \frac{1}{5}+ b = 9 \frac{3}{5} \ \ | (-4\frac{1}{5})\\ \\4 \frac{1}{5 }-4 \frac{1}{5}+ b = 9 \frac{3}{5}-4 \frac{1}{5}\\ \\b= 5\frac{2}{5}=5.4


kvasek [131]3 years ago
3 0
4 \frac{1}{5}  + b = 9  \frac{3}{5} \\\\b= 9  \frac{3}{5}-4 \frac{1}{5} \\\\b=5 \frac{2}{5}
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timofeeve [1]

Answer:

On the left, it would be + 1 for each blank, and on the right it would also be +1 for each blank.

Step-by-step explanation:

They are asking for the intervals between each number.

Hope this helps!

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2 years ago
Three divided by what equals 36
leva [86]
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6 0
3 years ago
molly school is selling tickets to the fall musical. on the first day of the ticket sales the school sold 13 adults tickets and
tester [92]

Answer:

Adult Ticket Price = $13

Child Ticket Price = $13

Step-by-step explanation:

Let price of adult ticket be "a" and child ticket be "c"

13 adult and 14 child equals $351, so we can write:

13a + 14c = 351

and

2 adult and 7 child equals $117, thus we can write:

2a + 7c = 117

We multiply 2nd equation by (-2) to get:

-2 * [2a + 7c = 117]

= -4a -14c = -234

Adding botht he "bold" equations, we get:

13a + 14c = 351

-4a -14c = -234

------------------------

9a = 117

a = 117/9 = 13

Now to find b, we use the value of a gotten in the first equation:

13a + 14c = 351

13(13) + 14c = 351

169 + 14c = 351

14c = 182

c = 182/14 = 13

Hence,

<em>Adult Ticket Price = $13</em>

<em>Child Ticket Price = $13</em>

3 0
3 years ago
The net of a square pyramid is shown: What is the surface area of the figure? (A)0.7625 square inch
aniked [119]

Answer:

C. 0.6625 square inches

Step-by-step explanation:

To get the area of the net of a square pyramid;

We need to find the are of the square base and the area of the four triangles;

Area of the square base = s²

                                         = (0.25 in)²

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Area of one triangle = 0.5 × b × h

                                 = 0.5 × 0.25 in × 1.2 in

                                 = 0.15 in²

Area of the four triangles = 0.15 in² × 4

                                          = 0.6 in²

Therefore;

Area of the net square pyramid = 0.0625 in² + 0.6 in²

                                                     = 0.6625 square inches

6 0
4 years ago
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