<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
y - 5 = -1(x + 3)
Step-by-step explanation:
Point slope form
y - y1 = m(x - x1) where m = slope and passing through point (x1 , y1)
In this case if the equation in point-slope form contains the point (–3, 5) and has slope –1 then the equation should be:
y - 5 = -1(x - (-3))
y - 5 = -1(x + 3)
Answer:
Vertex is (-8, 4) not one of the answers offered!
Step-by-step explanation:
Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.
Complete the square by squaring half the coefficient of <em>x </em>and adding it in the space.
Add 64 in the space you made, then compensate for that at the end of the expression by <u>subtracting</u> 
The x-coordinate of the vertex is the <u>opposite</u> of +8, the number inside the parentheses. The y-coordinate of the vertex is the number at the end of the expression.
V(-8, 4)
Answer: The answer is 50
Step-by-step explanation:
I did the test
