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3 years ago

How is all matter alike?

Chemistry

2 answers:

Alex_Xolod [135]3 years ago

5 0

Definite shape and definite volume makes them all alike

nignag [31]3 years ago

4 0

All matter (solid, liquid or gas) has a definite shape and occupies a specific volume.

<h2>Hope it helps...</h2>

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Given 1.00 grams of each of the following radioisotopes, Ca-37, U-238, P-32 and Rn-222,which would have the least remaining orig

erica [24]

1) Ca-37, with a half-life of 181.1(10) ms.

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4 years ago

How many electrons are there in second principal energy<br> level(n=2) of a phosphorus atom?

salantis [7]

Answer:

8 electrons

Explanation:

Phosphorous is the element of group 15 and third period. The atomic number of chlorine is 15 and the symbol of the element is P.

The electronic configuration of the element phosphorus is:-

$1s^22s^22p^63s^23p^3$

Thus, from the electronic configuration shown above,

In n = 2, the total number of electrons are 8 which are present in $2s^22p^6$

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4 years ago

Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have

Zepler [3.9K]

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

$1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}$

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

$m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g$

Thus, the price is:

$\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$$

Best regards!

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3 years ago

If the OH‑ ion concentration in an aqueous solution at 25.0 °C is 6.6 x 10‑4 M, what is the molarity of the H+ ion?

Tresset [83]

Answer:

1.5 × 10⁻¹¹ M

Explanation:

Step 1: Given data

Concentration of OH⁻ ([OH⁻]): 6.6 × 10⁻⁴ M

Temperature: 25°C

Concentration of H⁺ ([H⁺]): ?

Step 2: Consider the self-ionization of water

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Step 3: Calculate the molar concentration of H⁺

We will use the equilibrium constant for the self-ionization of water (Kw).

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / 6.6 × 10⁻⁴

[H⁺] = 1.5 × 10⁻¹¹ M

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4 years ago

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