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Kobotan [32]
3 years ago
6

Use the drop-down menus to identify the order of these images for the formation of our solar system.

Chemistry
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

Explanation:

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A 38.6 kg marble slab is shown above. What is it’s density? Give you’re answer to the nearest tenth
kykrilka [37]

Answer:

Density, d=24.68\ g/cm^3

Explanation:

Given that,

Mass of marble slab is 38.6 kg or 38600 g

The dimensions of the slab is 23 cm × 17 cm ×4 cm

We know that the density of an object is given in terms of its mass volume as follows :

d=\dfrac{\text{mass}}{\text{volume}}\\\\d=\dfrac{38600\ g}{1564\ cm^3}\\\\d=24.68\ g/cm^3

So, the density of the marble slab is 24.68\ g/cm^3

4 0
4 years ago
Identify the correct ranking of bonds or forces in order from strongest to weakest is:
Artemon [7]

The answer is (in order from strongest to weakest);

<span>covalent  </span>

<span>ionic  </span>

ion-dipole

H-bonding

dipole-dipole

<span>van der Waals</span>

A covalent<span> bond is hardest to break because it involves sharing of electrons by atoms while Van der Waals is weakest because they involve electrostatic attraction due to differentially induced dipoles between atoms and its strength is dependent on their distance apart. </span>






7 0
3 years ago
Before entering the cyclotron, the particles are accelerated by a potential difference V. Find the speed v with which the partic
vesna_86 [32]

Answer:

Speed, v=\sqrt{\dfrac{2qV}{m}}

Explanation:

The device which is used to accelerate charged particles to higher energies is called a cyclotron. It is based on the principle that the particle when placed in a magnetic field will possess a magnetic force. Just because of this Lorentz force it moves in a circular path.  

Let m, q and V are the mass, charge and potential difference at which the particle is accelerated.

The work done by the particles is equal to the kinetic energy stored in it such that,

qV=\dfrac{1}{2}mv^2

v is the speed with which the particles enter the cyclotron

So,

v=\sqrt{\dfrac{2qV}{m}}

So, the speed with which the particles enter the cyclotron is v=\sqrt{\dfrac{2qV}{m}}. Hence, this is the required solution.

7 0
3 years ago
The electron configuration for Helium (He) is shown below.
scoundrel [369]
Helium has an atomic number 2 and an atomic weight of 4 grams per mole. It is one of the noble gas (which means that it is stable) and also a nonmetal. Its electron configuration is 1s2. There are energy levels and they are s, p, d and f. The s level means that its maximum number of electrons is only 2.
6 0
3 years ago
Read 2 more answers
Calculate the pH of a 0.10 M solution of acidic acid HC2H3O2(aq) at 25 °C. Ka for HC2H3O2 = 1.8×10−5 at 25 °C g
TiliK225 [7]

Answer:

The answer is "3".

Explanation:

acetic acid Dissociation:  

CH_3COOH \ < - - - - - - - - - - - - - \ > CH_3COO^{-}+H^{+}\\\\

Dissociation constant of the Ka:

Ka = \frac{[CH3COO^{-}] [H^{+}]}{[CH_3COOH]}\\\\

using the ICE table:

CH_3COOH \ < - - - - - - - - - - - - - \ > CH_3COO^{-}+H^{+}\\\\ \to 1.8 \times 10^{-5} =\frac{( x  \times x) }{0.1-x} -------(2)

x is negligible compared to Ka.

1.8\times 10^{-5} = \frac{x^2}{0.10}\\\\x^2 = 1.8 \times 10^{-6}\\\\x = 1.34 \times 10^{-3}\\\\pH = -\log [H^{+}]

From the ICE table, [H^{+}] = x = 1.34 \times 10^{-3}

\to pH = -\log(1.34 \times 10^{-3}) = 3

5 0
3 years ago
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