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Ivan
2 years ago
11

WITH BRAINLIEST

Chemistry
1 answer:
TEA [102]2 years ago
4 0

Answer:

i want go with option 2

Explanation:

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The substance floats or sinks in another because of its relative
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Floats or sinks Because of its mass
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WILL RATE AND GIVE BRAINLIEST!!
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A) a disk formed  of long trails of stars coiled into a spiral

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Propane burns in oxygen to produce carbon dioxide and water what is the percent yeild
amid [387]

Answer:

The percentage yield is 78.2g

Explanation:

Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.

Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)

First we need to calculate the moles of propane

Moles of propane = \frac{42.8}{44.096} g.mol-1

                            = 0.971 moles

So, moles of CO2 from the moles of propane

1 mole of C3H8(g) = 3 moles of CO2(g)

So, 0.971 moles of C3H8(g) = ?

= 2.913 moles of CO2

So theoretical yield = 2.913 moles \times 44.0 g/mol

                               = 128.2 g

So, the actual mass of CO2 = percent yield \times  theoretical yield / 100 %

                                         = 61.0 % \times  128.2 g / 100 %

                                         = 78.2 g

the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g

4 0
3 years ago
If he(g) has an average kinetic energy of 8750 j/mol under certain conditions, what is the root mean square speed of cl2(g) mole
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<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas Average molar kinetic energy of the gas E = 1/2 M * (V_rms)^2 = 8750 ms/1 So (V_rms)^2 = (2 * 8750) / M Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3) Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3)) (V_rms)^2 = 8750/0.035 = 250000 So V_rms = âš 250000 = 500</span>
5 0
3 years ago
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During normal, relaxed respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. this is called t
Marianna [84]

During normal respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. This is called the<u> tidal volume</u>.

When a person is relaxed, the normal amount of air such a person breathes in and out is called the tidal volume. It is usually measured in millimeters. For the average adult male, it is 500ml, and the tidal volume of average adult female 400ml.

In order to regulate oxygen intake and expulsion of carbon dioxide, the lungs act as buffers in order to absorb the maximum amount of oxygen possible for respiration and other metabolic functions in the body.

When the tidal volume is above or below the 500ml mark, it could signal the presence of underlying pathological conditions like bronchitis, emphysema and asthma.

To find out more about tidal volume, visit:

brainly.com/question/17439101

#SPJ4

6 0
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