1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Digiron [165]
3 years ago
10

Allie is going to ship some gifts to family members, and she is considering two

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

a)10$

Step-by-step explanation:

You might be interested in
E = ( m V2)/2 rewrite this equation to solve for v<br><br><br><br> HELPP!!!!!
Vaselesa [24]

Answer: V 3

Step-by-step explanation:

6 0
3 years ago
Round 43,951,842 to the nearest hundred-thousand
GrogVix [38]
I think the answer would be 44,000,000 because if you roundthe 951 it goes to 1,000
4 0
3 years ago
Read 2 more answers
The graph shows the relationship between the number of pounds of oranges purchased and the total oost of oranges what is the cos
Ymorist [56]

Answer:

1

Step-by-step explanation:

1

5 0
3 years ago
If a and b are positive numbers, find the maximum value of f(x) = x^a(2 − x)^b on the interval 0 ≤ x ≤ 2.
Ad libitum [116K]

Answer:

The maximum value of f(x) occurs at:

\displaystyle x = \frac{2a}{a+b}

And is given by:

\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b

Step-by-step explanation:

Answer:

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = x^a (2-x)^b \text{ where } a, b >0

And we want to find the maximum value of f(x) on the interval [0, 2].

First, let's evaluate the endpoints of the interval:

\displaystyle f(0) = (0)^a(2-(0))^b = 0

And:

\displaystyle f(2) = (2)^a(2-(2))^b = 0

Recall that extrema occurs at a function's critical points. The critical points of a function at the points where its derivative is either zero or undefined. Thus, find the derivative of the function:

\displaystyle f'(x) = \frac{d}{dx} \left[ x^a\left(2-x\right)^b\right]

By the Product Rule:

\displaystyle \begin{aligned} f'(x) &= \frac{d}{dx}\left[x^a\right] (2-x)^b + x^a\frac{d}{dx}\left[(2-x)^b\right]\\ \\ &=\left(ax^{a-1}\right)\left(2-x\right)^b + x^a\left(b(2-x)^{b-1}\cdot -1\right) \\ \\ &= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right] \end{aligned}

Set the derivative equal to zero and solve for <em>x: </em>

\displaystyle 0= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right]

By the Zero Product Property:

\displaystyle x^a (2-x)^b = 0\text{ or } \frac{a}{x} - \frac{b}{2-x} = 0

The solutions to the first equation are <em>x</em> = 0 and <em>x</em> = 2.

First, for the second equation, note that it is undefined when <em>x</em> = 0 and <em>x</em> = 2.

To solve for <em>x</em>, we can multiply both sides by the denominators.

\displaystyle\left( \frac{a}{x} - \frac{b}{2-x} \right)\left((x(2-x)\right) = 0(x(2-x))

Simplify:

\displaystyle a(2-x) - b(x) = 0

And solve for <em>x: </em>

\displaystyle \begin{aligned} 2a-ax-bx &= 0 \\ 2a &= ax+bx \\ 2a&= x(a+b) \\  \frac{2a}{a+b} &= x  \end{aligned}

So, our critical points are:

\displaystyle x = 0 , 2 , \text{ and } \frac{2a}{a+b}

We already know that f(0) = f(2) = 0.

For the third point, we can see that:

\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(2- \frac{2a}{a+b}\right)^b

This can be simplified to:

\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b

Since <em>a</em> and <em>b</em> > 0, both factors must be positive. Thus, f(2a / (a + b)) > 0. So, this must be the maximum value.

To confirm that this is indeed a maximum, we can select values to test. Let <em>a</em> = 2 and <em>b</em> = 3. Then:

\displaystyle f'(x) = x^2(2-x)^3\left(\frac{2}{x} - \frac{3}{2-x}\right)

The critical point will be at:

\displaystyle x= \frac{2(2)}{(2)+(3)} = \frac{4}{5}=0.8

Testing <em>x</em> = 0.5 and <em>x</em> = 1 yields that:

\displaystyle f'(0.5) >0\text{ and } f'(1)

Since the derivative is positive and then negative, we can conclude that the point is indeed a maximum.

Therefore, the maximum value of f(x) occurs at:

\displaystyle x = \frac{2a}{a+b}

And is given by:

\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b

5 0
3 years ago
What is the slope of the line? y - 4= -7(x-6) Choose 1 answer: 1 А. 7 4. B 7 --7 2 3​
givi [52]

Step-by-step explanation:

the slope is always the factor of x.

in slope intercept form, as well as here in point slope form.

the important thing is that the y term is just brought to a simple positive y form (and not cy with c is different than 1).

and then, what you see on the other side as factor is x is the slope.

here : -7

the other numbers in the equating are irrelevant for the slope. they determine the "offset" of the line from (0, 0).

3 0
2 years ago
Other questions:
  • On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine
    12·2 answers
  • Please answer this correctly
    12·2 answers
  • What is the area of a piece of typing page 8.5" by 14"
    13·2 answers
  • If you have an infinite number of red, blue, yellow, and black socks in a drawer, how many socks must you pull out of the drawer
    5·1 answer
  • Camille bought 3 pounds of nuts for $10.35 what is the unit price per pound
    8·1 answer
  • A motor club has estimated that a 325 mile car trip will take 6 1/2 hours. What is the club assuming to be the average speed mil
    14·1 answer
  • On the number line shown below, which point could represent - 1.2 ?
    7·1 answer
  • How many students have used all three modes of transportation? solution please​
    10·1 answer
  • The graphs below have the same shape. What is the equation of the blue
    9·1 answer
  • Two factors of 24 add up to 11. What are they?​
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!