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4 years ago

Es -

Mathematics

2 answers:

sesenic [268]4 years ago

8 0

Answer:

The answer is D

Step-by-step explanation:

Andrews [41]4 years ago

8 0

Answer:

THE ANSWER D ON USATESTPREP

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Lan needs to find the area of the shaded region shown below. Which statements can he use to find the answer? Select three

Vsevolod [243]

Answer:

ABD

Step-by-step explanation:

6 0

4 years ago

Given cos(4x)+2 Find: Period, Shift, & Range

Yuki888 [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's see

$\bf \begin{array}{llccll}
cos(&4x&+0)&+2\\
&\uparrow &\uparrow &\uparrow \\
&B&C&D
\end{array} 
\\\\\\
period\qquad \cfrac{2\pi }{B}\implies \cfrac{2\pi }{4}\implies \cfrac{\pi }{2}
\\\\\\
\textit{horizontal/phase shift}\qquad \cfrac{C}{B}\implies \cfrac{0}{4}\implies 0\impliedby none
\\\\\\
\textit{vertical shift}\qquad D=+2\impliedby \textit{2 units up}$

now the range, how far up and down it goes on the y-axis

well, for the graph of cos(x), the range is, goes up to 1, down to -1, is all,

the midline is at 0

now, with a vertical shift of 2 upwards, it moves the midline by 2 units, used to be at 0, now is at y = 2, but the amplitude never changed, is goes up and down still one unit,

but with the midline at 2, goes up to 3 and down to 1, so the range is 3 ⩽ y ⩽ 1

4 0

4 years ago

Solve for p in the literal equation 2p + 3r = q. P =

anygoal [31]

Answer:

$p = \frac{ q - 3r }{ 2}$

Step-by-step explanation:

2p + 3r = q

2p + 3r - 3r = q - 3r [ subtract 3r from both sides ]

2p + 0 = q - 3r [ -3r + 3r = 0 ]

2p = q - 3r

$\frac{2p}{2} = \frac{q-3r}{2}$ [ divide by 2 on both sides ]

$p = \frac{ q - 3r }{ 2}$

5 0

3 years ago

I’ve been stuck on these for a while, can someone help? Thank you :) !!

natulia [17]

Answer:

6.32

254.34

Step-by-step explanation:

The lengths of the missing sides can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

first missing side

7² = 3² + x²

49 = 9 + x²

x² = 49 - 9

x² = 40

x = 6.32

second missing side

3² + 4²

9 + 16

= 25

√25 = 5

Area of a circle = πr²

Where : = π = pi = 3.14

3.14 x 9² = 254.34

6 0

3 years ago

What is the volume? 3 1/4 in 6 1/2 in 2 in

jeka94

Answer:

42¼ in³

Step-by-step explanation:

volume = 6½×2×3¼= 42¼ in³

7 0

3 years ago

Read 2 more answers