First things first. Solve the equation for y, getting it into y = mx + b form so it's easy to determine the slope. 5x + 2y = 12 so 2y = -5x + 12. Dividing everything by 2 we get

. So the slope is -5/2. Parallel lines have the same slope, so we will have a slope of -5/2 in our new equation, we just have to find out what that equation is. We have an x and a y value from the point, so we will use that, along with the slope, to find b, the y-intercept.

and 4 = 5 + b. So b = -1. Now let's write the equation:

. And there you go!
Answer:
The Answer is D or 12^x+1 (12^h - 1) / h
Step-by-step explanation:
Answer:
253,498.1?
Step-by-step explanation:

- Given - <u>two </u><u>points </u><u>P </u><u>(</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>1</u><u>0</u><u> </u><u>)</u><u> </u><u>and </u><u>R </u><u>(</u><u> </u><u>1</u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>)</u><u> </u><u>on </u><u>the </u><u>c</u><u>artesian </u><u>plane</u>
- To find - <u>distance </u><u>between </u><u>the </u><u>two </u><u>points</u>
<u>Using </u><u>the </u><u>distance </u><u>formula</u> ~

we have ,

<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>,</u><u> </u><u>we </u><u>get</u>

hope helpful :)
9514 1404 393
Answer:
- non-leap years: 31/365
- leap years: 31/366
Step-by-step explanation:
As a fraction of the number of days in a calendar year, it will depend on whether the year is a leap year.
non-leap years have 365 days, so 31 days is 31/365 years.
leap years have 366 days, so 31 days is 31/366 years.
_____
If you're asking for the purpose of computing interest, you need to be aware that "ordinary interest" counts 360 days in a year. 31 days would be 31/360 years. "Exact interest" counts 365 days in a year, so 31 days would be 31/365 years.
In astronomy, the definitions of "day" and "year" may vary, depending on the frame of reference and what direction in space marks the boundary of the period. The precise fraction will depend on how you define these terms and where the clock is located.