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ICE Princess25 [194]
3 years ago
14

Write a word sentences as an expression. A number x decreased by 3 is 5.

Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer:

c: x-3=5

Step-by-step explanation:

what grade is this for?

hope this helps

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Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
If f(x) = 4x + 12x and g(x) = 5x - 1, find (f + g)(x).
egoroff_w [7]

Answer:

= 21x - 1

Step-by-step explanation:

= (4x + 12x) + (5x - 1)

= 4x + 12x + 5x - 1

= 16x + 5x - 1

= 21x - 1

3 0
3 years ago
The cost to rent an instrument is $05 for the first month. It costs $30 for each additional
mihalych1998 [28]

Answer:

total cost, or c = number of months rented after first month, or x, times $30 + $5

c=30x+5

Step-by-step explanation:

6 0
3 years ago
4t + 2u2 - u3 ; t=2 u=1
melisa1 [442]
9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
3 0
3 years ago
The school cafeteria served 2,680 cups of milk in March and 1,480 cups of milk in April. How many quarts of milk did the cafeter
nignag [31]

Answer:

<h2 />

Step-by-step explanation:

ghhbb\sqrt{x} btw go check out fidgetshopbutterflys on and follow    on tiktok

8 0
3 years ago
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