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Blababa [14]
3 years ago
6

The area of circle b is 36 times greater than the area of circle

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0
I would say D I hope this helps
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Y+7=4/3(x+3) <br><br>A point on this line that is apparent from the given equation is?
Assoli18 [71]

Answer:

(-3, -7)

General Formulas and Concepts:

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

Point-Slope Form:   y + 7 = 4/3(x + 3)

<u>Step 2: Break function</u>

Slope <em>m</em> = 4/3

Point (-3, -7)

3 0
3 years ago
An open box with a square base is to have a volume of 18 ft3. (a) find a function that models the surface area a of the box in t
stiks02 [169]
2.7144 ft
hope i helped. your welcome. peace
5 0
3 years ago
Scale factor=0.75 is enlarge , reduce , or preserve ?
zvonat [6]

Answer:

Reduce

Step-by-step explanation:

It will reduce because the factor is less than 1 so it cannot enlarge and it is not the same as the 1 so it cannot preserve.

6 0
3 years ago
Read 2 more answers
When the author observed a sobriety checkpoint conducted by the Dutchess County Sheriff Department, he saw that 676 drivers were
jek_recluse [69]

Answer:

The probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

Step-by-step explanation:

As the event is indicated as I for the drivers who are intoxicated, the value of I¯ is for the drivers who are not intoxicated. Its value is calculated as follows

P(I¯)=1-P(I)

P(I¯)=1-0.00589

P(I¯)=0.99411

So the probability of drivers who are not intoxicated is P(I¯) and is given as 0.99411.

6 0
3 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
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