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Mila [183]
3 years ago
14

Limx→+∞​ (x-(lnx)^2) =?​

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

\lim_{x\to\infty}(x-\ln(x)^2) \\\lim_{x\to\infty}(x-2\ln(x)) \\\lim_{x\to\infty}\Big(x\Big(1-\dfrac{2\ln(x)}{x}\Big)\Big) \\\lim_{x\to\infty}x\cdot\lim_{x\to\infty}\Big(1-\dfrac{2\ln(x)}{x}\Big) \\\infty\cdot\Big(\lim_{x\to\infty}(1)-\lim_{x\to\infty}\Big(\dfrac{2\ln(x)}{x}\Big)\Big) \\\infty\cdot(1-2\lim_{x\to\infty}(1/x)) \\\infty\cdot(1-0) \\\infty\cdot1=\boxed{\infty}

Hope this helps.

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(This will make it much easier to compare.)

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And don't forget to convert the selective decimals that we converted earlier back into fractions!

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Hope this helps! 
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