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4 years ago

A metal object is four feet away from a magnet. If you move the object two feet closer toward the

Physics

1 answer:

Temka [501]4 years ago

8 0

The flux will be 4 times stronger ( due to the inverse square law )

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Locate the element xenon (Xe) on the periodic table and click on the square. What class of element is xenon found in?

musickatia [10]

Noble gas, that is the correct answer on e2020!

4 0

3 years ago

Read 2 more answers

How does Newton's first law of motion affect people in a car crash?

kap26 [50]

Answer:

When the car crashes there is no balanced force acting on the person so they continue forward in the car

Explanation:

3 0

4 years ago

A beam of unpolarized light with a power of 1.0 mW passes through two ideal linear polarizers in series. An ideal polarizerabsor

Mashutka [201]

Answer:

the axes of the two polarizers are aligned, the angle between this axis must be zero

Explanation:

Polarizers are anisotropic systems where absorption is selective in each axis, in this case they indicate that on an axis they let 100% pass and perpendicular to this axis no light passes.

The first polarizer defines a direction of light that of its axis, it is said that the light is polarized, when this light reaches the second polarized, so that it can pass the axis must be in the direction of the polarized beam.

In summary, the axes of the two polarizers are aligned, the angle between this axis must be zero

3 0

3 years ago

A record of travel along a straight path is as follows:

nignag [31]

Answer:

a) Total displacement = 3986.54 m

b) Average speeds

Leg 1 -> 11.22 m/s

Leg 2 -> 22.44 m/s

Leg 3 -> 11.20 m/s

Complete trip -> 21.63 m/s

Explanation:

a) Leg 1:

Initial velocity, u = 0 m/s

Acceleration , a = 2.04 m/s²

Time, t = 11 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 0 x 11 + 0.5 x 2.04 x 11²

s = 123.42 m

Leg 2:

We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Acceleration , a = 2.04 m/s²

Time, t = 11 s

Substituting

v = 0 + 2.04 x 11 = 22.44 m/s

We have equation of motion s= ut + 0.5 at²

Initial velocity, u = 22.44 m/s

Acceleration , a = 0 m/s²

Time, t = 2.85 min = 171 s

Substituting

s= ut + 0.5 at²

s = 22.44 x 171 + 0.5 x 0 x 171²

s = 3837.24 m

a) Leg 3:

Initial velocity, u = 22.44 m/s

Acceleration , a = -9.73 m/s²

Time, t = 2.31 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 22.44 x 2.31 + 0.5 x -9.73 x 2.31²

s = 25.88 m

Total displacement = 123.42 + 3837.24 + 25.88 = 3986.54 m

Average speed is the ratio of distance to time.

b) Leg 1:

$v_{avg}=\frac{123.42}{11}=11.22m/s$

Leg 2:

$v_{avg}=\frac{3837.24}{171}=22.44m/s$

Leg 3:

$v_{avg}=\frac{25.88}{2.31}=11.20m/s$

Complete trip:

$v_{avg}=\frac{3986.54}{11+171+2.31}=21.63m/s$

5 0

3 years ago

If a person walks 1km north , 5 km West , 3km south and 7km east, find the resultant displacement vector

raketka [301]

Y = +1-3 = -2

X = -5+7 = +2

D = √2^2-2^2 = 2√1+1 = 2√2 km

3 0

3 years ago