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VikaD [51]
3 years ago
14

A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a

Physics
1 answer:
vesna_86 [32]3 years ago
7 0

I thought you were going to ask for the resistance of the unknown
series resistor.  Since you only want the equivalent resistance of the
circuit, you don't even need to know the resistance of the lamp.

I = E / R

Current through the circuit = (voltage of the battery) / (circuit resistance).
  
                                                  0.5 = (12) / R

Multiply each side by  'R' :    (0.5) R = 12

Multiply each side by  2 :      <em>R = 24 ohms</em>


(Since the resistance of the lamp is 10 ohms, the
unknown series resistor is the other 14 ohms.)
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A very long, uniformly charged cylinder has radius R and linear charge density λ. Find the cylinder's electric field strength ou
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The cylinder's electric field magnitude, at a distance <em>r</em> from the axis of the cylinder (greater than the cylinder's radius), is equal to E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3>Further explanation</h3>

Matter is the building block of everything that we encounter in our lives. Matter is made of atoms, which are in turn made of tiny particles which are called electrons, protons, and neutrons. The ammount of these 3 elements, and their topological configuration in the atoms, is what determines what a certain element is (like Carbon, Hydrogen, Iron, etc).

In some cases, some elements may lose or gain some electrons. Regarded that this missing or extra electrons are not very high in number, the material doesn't lose any of its properties, however it will always try to get its number of electrons back to normal. This is when we say that an element has a <em>charge</em>, which is a measure of how much electrons a body needs to get back to normal. A body has positive charge if it lacks electrons, and has negative charge if it has extra electrons.

This charge causes the material to have an Electric field, which is a measure of how much does it attract or repel electrons. In the case of our problem, we need to compute exactly that, the Electric field. In our problem, we have an infinitely long cylinder with a linear charge density \lambda, this means that all parts of the cylinder have the same charge, and due to symmetry, the electric field is constant on the angular and longitudinal directions of the cylinder.

This makes easy to apply Gauss' Law, since for a Gaussian curve in the shape of a concentric cylinder (with a higher radius than that of our charged cylinder) we can write:

\Phi = \frac{\lambda \cdot L}{\epsilon_0}

Where \Phi is called the Electric flux. Since the electric field is constant for a given distance <em>r</em> from the axis of the cylinder we can write that:

\Phi = E \cdot 2\pi r \cdot L

Joining both our expressions we can get that:

E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3 /><h3>Learn more</h3>
  • Description on Electric fields: brainly.com/question/8971780
  • Relation between electric fields and magnetism: brainly.com/question/2838625
  • How can we use electric charges: brainly.com/question/10427437
<h3>Keywords</h3>

Electrons, protons, electric field, cylinder, electric flux

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