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VikaD [51]
4 years ago
14

A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a

Physics
1 answer:
vesna_86 [32]4 years ago
7 0

I thought you were going to ask for the resistance of the unknown
series resistor.  Since you only want the equivalent resistance of the
circuit, you don't even need to know the resistance of the lamp.

I = E / R

Current through the circuit = (voltage of the battery) / (circuit resistance).
  
                                                  0.5 = (12) / R

Multiply each side by  'R' :    (0.5) R = 12

Multiply each side by  2 :      <em>R = 24 ohms</em>


(Since the resistance of the lamp is 10 ohms, the
unknown series resistor is the other 14 ohms.)
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Salma is riding her bicycle. She rides 25.6 kilometers in 4 hours. What is her speed?
Musya8 [376]

Answer:

6.4 kilometers per hour

Explanation:

Just do the amount of distance she covers divided by how many hours she rides to get the answer. In this case, its 25.6 divided by 4 which equals 6.4

3 0
3 years ago
- A capacitor's dielectric material is a vacuum. The capacitor's dielectric constant, or K, will be equal to
dlinn [17]

If  a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.

<u>Explanation:</u>

Relative permittivity of  a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.

It is given by the expression

k=k=ε /ε0

where ε denotes absolute permittivity and  ε0 denotes permittivity of vacuuum.

Absolute permittivity  ε of vacuum= ε0

therefore k= ε0/ ε0=1

dielectric constant of vacuum is 1 .

4 0
3 years ago
A 2.0-kg projectile is fired with initial velocity components v0x = 30 m/s and v0y = 40 m/s from a point on the Earth's surface.
Alexxandr [17]

Answer:

Kinetic energy of the projectile at the vertex of the trajectory: 900\; {\rm J}.

Work done when firing this projectile: 2500\; {\rm J}.

Explanation:

Since the drag on this projectile is negligible, the horizontal velocity v_{x} of this projectile would stay the same (at 30\; {\rm m\cdot s^{-1}}) throughout the flight.

The vertical velocity v_{y} of this projectile would be 0\; {\rm m\cdot s^{-1}} at the vertex (highest point) of its trajectory. (Otherwise, if v_{y} > 0, this projectile would continue moving up and reach an even higher point. If v_{y} < 0, the projectile would be moving downwards, meaning that its previous location was higher than the current one.)

Overall, the velocity of this projectile would be v = 30\; {\rm m\cdot s^{-1}}\! when it is at the top of the trajectory. The kinetic energy \text{KE} of this projectile (mass m = 2.0\; {\rm kg}) at the vertex of its trajectory would be:

\begin{aligned} \text{KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2} \times 2.0\; {\rm kg} \times (30\; {\rm m\cdot s^{-1}})^{2} \\ &= 900\; {\rm J} \end{aligned}.

Apply the Pythagorean Theorem to find the initial speed of this projectile:

\begin{aligned}v &= \sqrt{(v_{x})^{2} + (v_{y})^{2}} \\ &= \left(\sqrt{900 + 1600}\right)\; {\rm m\cdot s^{-1}} \\ &= 50\; {\rm m\cdot s^{-1}}\end{aligned}.

Hence, the initial kinetic energy \text{KE} of this projectile would be:

\begin{aligned} \text{KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2} \times 2.0\; {\rm kg} \times (50\; {\rm m\cdot s^{-1}})^{2} \\ &=2500\; {\rm J} \end{aligned}.

All that energy was from the work done in launching this projectile. Hence, the (useful) work done in launching this projectile would be 2500\; {\rm J}.

7 0
2 years ago
Maximum range of a projectile is 1.6 m. Then the velocity of projection will be..... (g=10m/s)
qaws [65]

Answer:

4 m/s

Explanation:

From the question given above, the following data were obtained:

Maximum range (Rₘₐₓ) = 1.6 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

The initial velocity of the projectile can be obtained as follow:

Rₘₐₓ = u² / g

1.6 = u² / 10

Cross multiply

u² = 1.6 × 10

u² = 16

Take the square root of both side

u = √16

u = 4 m/s

Therefore, the velocity of the projectile is 4 m/s

6 0
3 years ago
How much larger is the acceleration with two people pushing on one side of the cart compared to only one person pushing the cart
il63 [147K]
As we said to the two people name A and the single person nameB.as every person make an acceleration 60ms2.so group A has more acceleration then group B. because in A there are two person so we add 60+60=120ms2. so group A can produce 120ms2 while groupB can produce 60ms2. i hope it will help you.

6 0
3 years ago
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