Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
I think the answer is 10 full 6Kg boxes
my first answer if you saw it was miscalculated, sorry.
Answer:
The volume(V) of gas will increase when the pressure of the gas decreases assuming all the other variables are held constant.
Step-by-step explanation:
P = Pressure of the ideal gas
V = Volume of the ideal gas
n = Moles of the ideal gas
R = Universal gas constant
T = Temperature of the ideal gas
Given:
y varies directly with x
y = 8 when x = -6
what is the value of y when x = -2?
y = kx
we need to get the constant of variation.
8 = k(-6)
8/-6 = k
4/-3 = k or - 1 1/3
y = -4/3 (-2)
y = (-4*-2) / 3
y = 8 / 3
y = 2 2/3 OR 2.67
The correct answer is Choice B. y = -1.33x ; 2.67
