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givi [52]
3 years ago
14

Benzoic acid is a white crystalline powder used as a food preservative the compound contains 68.8% carbon, 5.0% hydrogen and 26.

2% oxygen by mass what is the empirical formula
Chemistry
1 answer:
KiRa [710]3 years ago
4 0
So in this task first I think you should use the formula of the: Density/percentage

68.8% divided 26.2%= 2.625954198473282

2.625954198473282 X =

13.12977099236641
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why would it not be necessary to heat the air in the balloon as much if the air outside the balloon is colder?
RUDIKE [14]

Hot-air balloons float because the air caught inside the balloon is heated up by a burner, making it less dense than the air outside. As the burner heats the air, it expands and some of the air escapes; that's what makes it less dense

5 0
3 years ago
Read 2 more answers
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcy
Shtirlitz [24]

Answer:

5-chloro-2-methylcyclohexanol    

Explanation:  

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.  

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. <em><u>In this case, the priority functional group is the alcohol group</u></em>, <u><em>so we will start the counting of the carbons in this group.</em></u> Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, <em><u>in this case, we can assign the number 2 to the methyl group and 5 to the chloride group</u></em>, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.                      

Since the other options involve: <u>high countings for the susbtituents groups  (</u><u>3</u><u>-chloro-</u><u>6</u><u>-methylcyclohexanol)</u>, <u>wrong assignation of priority functional group (</u><u>1-chloro</u><u>-4-methylcyclohexanol), wrong sequence of counting in the compound (</u><u>2-methyl-3-chloro</u><u>cyclohexanol) and no alphabetical order to name the compound (2-</u><u>methyl</u><u>-5-</u><u>chloro</u><u>cyclohexanol), </u><u>the correct option is:</u>            

5-chloro-2-methylcyclohexanol  

Have a nice day!

4 0
4 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

5 0
3 years ago
Balance the equation, show steps:<br><br>Ag (s) + H2S (g) + O2 (g) ⟶ Ag2S (s) + H2O (l)
ehidna [41]
4Ag + 2H2S + O2 -> 2Ag2S + 2H20 i’m pretty sure that’s correct
5 0
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