Answer:
c. Compound 2 is more acidic because its conjugate base is more resonance stabilized
Explanation:
You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.
The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.
CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.
Answer : The must be administered.
Solution :
As we are given that a vial containing radioactive selenium-75 has an activity of .
As, 3.0 mCi radioactive selenium-75 present in 1 ml
So, 2.6 mCi radioactive selenium-75 present in
Conversion :
Therefore, the must be administered.
Answer:
will form a precipitate of insoluble
when aqueous
is added.
Explanation:
According to solubility rule-
all carbonates are insoluble except group IA compounds and
all salts of sodium are soluble
When is added to given solutions, a double displacement reaction takes place in each solution to form a sodium salt and a carbonate salt.
So, in accordance with solubility rule, addition of into
will result precipitation of insoluble
Reaction: