The following two compounds are constitutional isomers. Identify which of these is expected to be more acidic, and explain your
choice. a. The compound below is more acidic because its conjugate base is more resonance stabilized.b. The conjugate base of the other compound is not as much resonance stabilized.c. The compound below is more acidic because its conjugate base is more resonance stabilized.d. The conjugate base of the other compound is not as much resonance stabilized.e. The compound below is more acidic because its conjugate base is resonance stabilized.f. The conjugate base of the other compound is not resonance stabilized.Tg. he compound below is more acidic because its conjugate base is resonance stabilized.h. The conjugate base of the other compound is not resonance stabilized.
1 answer:
Answer:
c. Compound 2 is more acidic because its conjugate base is more resonance stabilized
Explanation:
You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.
The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.
CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.
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Answer:
The answer is "Option B"
Explanation:
From the query, the following knowledge is derived:
Yield in percentage = 47%
Performance of theory = 4860 g
Actual yield Rate =?
The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:
Now We can obtain the percent yield as followed using the above formula:
The value of the Actual yield Rate =
The Actual yield Rate= 2284.2 g.