The following two compounds are constitutional isomers. Identify which of these is expected to be more acidic, and explain your
choice. a. The compound below is more acidic because its conjugate base is more resonance stabilized.b. The conjugate base of the other compound is not as much resonance stabilized.c. The compound below is more acidic because its conjugate base is more resonance stabilized.d. The conjugate base of the other compound is not as much resonance stabilized.e. The compound below is more acidic because its conjugate base is resonance stabilized.f. The conjugate base of the other compound is not resonance stabilized.Tg. he compound below is more acidic because its conjugate base is resonance stabilized.h. The conjugate base of the other compound is not resonance stabilized.
1 answer:
Answer:
c. Compound 2 is more acidic because its conjugate base is more resonance stabilized
Explanation:
You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.
The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.
CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.
You might be interested in
Answer : The value of and K is, -180 kJ/mol and
Explanation :
The balanced cell reaction will be,
The half-cell reactions are:
Oxidation reaction (anode) :
Reduction reaction (cathode) :
Relationship between standard Gibbs free energy and standard electrode potential follows:
where,
= standard Gibbs free energy
F = Faraday constant = 96500 C
n = number of electrons in oxidation-reduction reaction = 2
= standard electrode potential of the cell = 0.93 V
Now put all the given values in the above formula, we get:
Now we have to calculate the value of 'K'.
where,
= standard Gibbs free energy = -180 kJ/mol
R = gas constant =
T = temperature = 298 K
K = equilibrium constant = ?
Now put all the given values in the above formula 1, we get:
Therefore, the value of and K is, -180 kJ/mol and