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Neporo4naja [7]
3 years ago
15

PLEASE HELP!!!!!!!!!!!!!!

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0

Answer:

angle = 50.8° (to the nearest tenth of a degree)

Step-by-step explanation:

In a right triangle:

  • The angle between the shorter leg and the hypotenuse is the larger acute angle of the triangle.
  • The angle between the longer leg and the hypotenuse is the smaller acute angle of the triangle.

We have been given the measures of the <u>shorter leg</u> and the <u>hypotenuse</u>, so the angle between them is the <u>larger acute angle</u> (which we need to find).

shorter leg = 3√6 cm

hypotenuse = 3√15 cm

So to find the angle, we need to use the trig ratio: cos(\theta)=\frac{adjacent}{hypotenuse}

If \theta is the angle, then the short leg is the "adjacent" side to the angle and the "hypotenuse" is the hypotenuse.

Substituting the given values:

cos(\theta)=\frac{3\sqrt{6} }{3\sqrt{15} }

⇒ \theta=arccos(\frac{3\sqrt{6} }{3\sqrt{15} })=50.76847952..

Therefore, the angle = 50.8° (to the nearest tenth of a degree)

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Answer:

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second box (y): 12

Step-by-step explanation:

HIJ is a translation of HIJ

translation just means you move the whole thing without any rotations dialations ect just moving it

from the blue shape it is asking what do you have to do to the x and y to get to the purple shape

you have to go +_x and take away _y

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same thing for the y value im going to use J again

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6 0
4 years ago
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