Just solve the equations:
<span>A) X - Y = 11
B) 2x + Y = 19
Multiply A) by -2
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<span>A) -2X +2Y = -22 then add to B)
</span><span>B) 2x + Y = 19
3Y = -3
Y=-1
</span>
<span>A) X - -1 = 11
x = 10
</span>
3.84/16 = 0.24 per tangerine
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
hi,
first let's count the marbles : 1+3+2 = 6
so picking a red is 1/6
a green is : 3/6
a bleu is : 2/6
Getting 10% a month is the best option if she put $500 in. That would be $50 the first month. $55 the second month etc. -- which would be more than the $500 in answer 1.
