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marin [14]
2 years ago
12

A 1500 kg car traveling due east at 20 m/s slows to a stop in 5.0 seconds. What is the impulse?

Physics
2 answers:
lbvjy [14]2 years ago
5 0

Answer:

Hans-Georg Gadamer (1900-2002) was an influential German philosopher of the twentieth century, inspiring a variety of scholastic disciplines from aesthetics to theology. In suggesting understanding was interpretation and vice versa, Gadamer identifies language acting as the medium for understanding. Gadamer’s philosophy of hermeneutics has major implications for education and formal schooling because Hermeneutics help to know the knowledge a student has prior to the lesson. This helps in the dialogue about a subject matter and therefore, the philosophy of Hermeneutics when applied in classroom helps the teachers pass information easily and effectively, hence, the learners capture the whole content of a topic.

Explanation:

horrorfan [7]2 years ago
3 0
30,000N/S this is because impulse =force*time therefore to get the force mass*acceleration. Using Newton’s first law of motion to find acceleration ie. V-u/t =-4m/s^2
Equating to the question 1500*4=6000N *5=30,000N/S
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An air hockey game has a puck of mass 30 grams and a diameter of 100 mm. The air film under the puck is 0.1 mm thick. Calculate
OverLord2011 [107]

Answer:

time required after impact for a puck is 2.18 seconds

Explanation:

given data

mass = 30 g = 0.03 kg

diameter = 100 mm = 0.1 m

thick = 0.1 mm = 1 ×10^{-4} m

dynamic viscosity = 1.75 ×10^{-5} Ns/m²

air temperature = 15°C

to find out

time required after impact for a puck to lose 10%

solution

we know velocity varies here 0 to v

we consider here initial velocity = v

so final velocity = 0.9v

so change in velocity is du = v

and clearance dy = h

and shear stress acting on surface is here express as

= µ \frac{du}{dy}

so

= µ  \frac{v}{h}   ............1

put here value

= 1.75×10^{-5} × \frac{v}{10^{-4}}

= 0.175 v

and

area between air and puck is given by

Area = \frac{\pi }{4} d^{2}

area  =  \frac{\pi }{4} 0.1^{2}

area = 7.85 × \frac{v}{10^{-3}} m²

so

force on puck is express as

Force = × area

force = 0.175 v × 7.85 × 10^{-3}

force = 1.374 × 10^{-3} v    

and now apply newton second law

force = mass × acceleration

- force = mass \frac{dv}{dt}

- 1.374 × 10^{-3} v = 0.03 \frac{0.9v - v }{t}

t =  \frac{0.1 v * 0.03}{1.37*10^{-3} v}

time = 2.18

so time required after impact for a puck is 2.18 seconds

3 0
3 years ago
2. Michelle bought 15.6 yards of fabric. She used 5.43 yards in her art 10 points
viktelen [127]
Do find the percentage you:
5.43/15.6=0.34

Time by 100:
34%

Closest answer is 35%

Hope this helps ;)
8 0
3 years ago
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