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Butoxors [25]
3 years ago
15

Two identical waves are moving in the same direction with the same speed. If the amplitude of the combination of the two waves i

s 1.5 times that of one of the original amplitudes, what is the phase difference between these two waves
Physics
1 answer:
umka2103 [35]3 years ago
4 0

Answer:

The phase difference between these two waves is 141.1⁰

Explanation:

The displacement of the wave is given as;

Y = y_xSin(Kx - \omega t)+y_xSin(Kx- \omega t + \phi)\\\\Y = 2y_xCos(\frac{1}{2} \phi)Sine(Kx- \omega t + \frac{1}{2} \phi)

Amplitude, A = 2yₓCos(¹/₂Φ)

Since the amplitude of the combination is 1.5 times that of one of the original amplitudes = yₓ = 1.5 × A = 1.5A

A = 2(1.5A)Cos(¹/₂Φ)

A = 3ACos(¹/₂Φ)

¹/₃ =  Cos(¹/₂Φ)

(¹/₂Φ) = Cos ⁻(0.3333)

(¹/₂Φ) = 70.55°

Φ = 141.1°

The phase difference between these two waves is 141.1⁰

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To learn more about Young's double-slit experiment: brainly.com/question/28108126

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im not too sure about this one tho but i hope it helps

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