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3 years ago

8-m/n +p^2 when m=8,n=2,p=2

Mathematics

1 answer:

expeople1 [14]3 years ago

8 0

8 - m/n + p^2

8 - 8/2 + 2^2

8 - 4 + 4

4 + 4

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F=-GMn/D^2 solve for M

notka56 [123]

M=FD^2/(-Gn)
here is the solution

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3 years ago

The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of

Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

${\boxed{\sf Area=LB}}$

Substitute the values

$\hookrightarrow\sf x (6x-4)=20$

$\hookrightarrow\sf 6x^2-4x=20$

$\hookrightarrow\sf 6x^2-4x-20=0$

Here a=6, b=-4, c=-20.
use quadratic formula

$\hookrightarrow\sf x=\dfrac {1}{3}+\dfrac {1}{3}\sqrt {31} \quad or \quad \dfrac {1}{3}+\dfrac {-1}{3}\sqrt {31}$

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2 years ago

A machine covers 5/8 square foot in 1/4 hour

VLD [36.1K]

The question is incomplete. Here is the complete question:

A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?

Answer:

2.5 square feet per hour

Step-by-step explanation:

Given:

Area covered by a machine = $frac{5}{8}\ ft^2$

Time taken to cover the given area = $\frac{1}{4}\ h$

Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.

Here, the first quantity is the area covered and the second quantity is the time taken.

So, unit rate is the area covered by the machine in 1 hour.

In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,

$Unit\ rate=\frac{Total\ area\ covered}{Total\ time\ taken}\\\\Unit\ rate=(\frac{5}{8}\ ft^2)\div (\frac{1}{4}\ h)\\\\Unit\ rate=\frac{5}{8}\times \frac{4}{1}\ ft^2/h\\\\Unit\ rate=\frac{20}{8}=2.5\ ft^2/h$

Thus, the unit rate is 2.5 square feet per hour.

5 0

3 years ago

OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

3 0

3 years ago

− 3 − {3 − [ − 3(2 +4) − ( − 2)]}

Readme [11.4K]

-22 is the answer i got

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2 years ago