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bonufazy [111]
3 years ago
11

Need answers for 9,11,15,17,26,36

Mathematics
1 answer:
Serggg [28]3 years ago
4 0
9: 1/9
11: 1/25
15: -1
17: 1
26: 1/k^4
36: 14m^2/t^5
The ^ sign is the exponent so like 2^7 would be 2 to the 7th power.
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Solve for x,y,z on the triangle
nordsb [41]
X = 64.5
Y= 25.5
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Use the definition to find an expression for the area under the curve y = x3 from 0 to 1 as a limit. lim n→∞ n i = 1 R (b) The f
Harlamova29_29 [7]

The summand (R?) is missing, but we can always come up with another one.

Divide the interval [0, 1] into n subintervals of equal length \dfrac{1-0}n=\dfrac1n:

[0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right]

Let's consider a left-endpoint sum, so that we take values of f(\ell_i)={\ell_i}^3 where \ell_i is given by the sequence

\ell_i=\dfrac{i-1}n

with 1\le i\le n. Then the definite integral is equal to the Riemann sum

\displaystyle\int_0^1x^3\,\mathrm dx=\lim_{n\to\infty}\sum_{i=1}^n\left(\frac{i-1}n\right)^3\frac{1-0}n

=\displaystyle\lim_{n\to\infty}\frac1{n^4}\sum_{i=1}^n(i-1)^3

=\displaystyle\lim_{n\to\infty}\frac1{n^4}\sum_{i=0}^{n-1}i^3

=\displaystyle\lim_{n\to\infty}\frac{n^2(n-1)^2}{4n^4}=\boxed{\frac14}

8 0
4 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!
Shalnov [3]

Answer:

D i think sorry if wrong

Step-by-step explanation:

8 0
3 years ago
Find the solution(s) for x in the equation below.
Kobotan [32]

Answer:

D) x=5, x=-5.

Step-by-step explanation:

x^2-25=0

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5 0
3 years ago
Solve 5x 2 - 7x + 2 = 0 by completing the square. What are the solutions?
Alexeev081 [22]

Answer:

x=\frac{2}{5} or x=1

Step-by-step explanation:

The given quadratic equation is

5x^2-7x+2=0

Group the constant terms on the right hand side.

5x^2-7x=0-2

5x^2-7x=-2

Divide through by 5.

x^2-\frac{7}{5}x=-\frac{2}{5}

Add the square of half the coefficient of x., which is (\frac{1}{2}\times- \frac{7}{5})^2=\frac{49}{100} to both sides of the equation.

x^2-\frac{7}{5}x+\frac{49}{100}=-\frac{2}{5}+\frac{49}{100}

The left hand side is now a perfect square.

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Take the square root of both sides;

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x-\frac{7}{10}=\pm \frac{3}{10}

x=\frac{7}{10}\pm \frac{3}{10}

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x=\frac{4}{10} or x=\frac{10}{10}

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5 0
3 years ago
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