Which car is faster A or B

During a race, a runner runs with an average velocity of 4.26 m/s toward city hall. What is the runner’s displacement after 167s

Artyom0805 [142]

Answer:

d = 711.42 m

Explanation:

Given that,

The average velocity of a runner, v = 4.26 m/s

Time, t = 167 s

We need to find the runner's displacement.

The average velocity of an object is equal to the displacement per unit time. It can be given by :

$v=\dfrac{d}{t}\\\\d=vt\\\\d=4.26\ m/s\times 167\ s\\\\d=711.42\ m$

So, the runner's displacement is 711.42 m.

3 0

3 years ago

How many meters are there in 1865 cm

finlep [7]

Answer:

18.65

Explanation:

To solve, divide 1865 by 100

1865/100= 18.65

Hope this helps! :) If correct pls mark brainliest :)

7 0

3 years ago

Read 2 more answers

To drive a typical car at 40 mph on a level road for one hour requires about 3.2 × 107 J of energy. Suppose we tried to store th

tatiyna

Answer:

9000RPM

Explanation:

"Angular velocity" is directly related to kinetic energy, that is, the Kinetic energy equation would allow an approximation to the resolution investigated in the problem.

The equation for KE is given by:

$KE = \frac{1}{2} lw ^ 2$

Now, starting from there towards the <em>Angular equation of kinetic energy</em>, the moment of inertia (i) is used instead of mass (m), and angular velocity (w) instead of linear velocity (V)

That's how we get

$KE_{Angular} = \frac{1}{2} Iw^2$

calculating the inertia for a solid cylindrical disk, of

m = 400kg

r = 1.2 / 2 = 0.6m

$I_{disk} = \frac{1}{2} mr^2 = (0.5) (400) (0.6)^2 = 72 kgm^2$

We understand that the total kinetic energy is 3.2 * 10 ^ 7J, like this:

$3.2*10^7 = \frac{1}{2} Iw^2 = (0.5) (72) w^2 = 36w^2$ $w^2 = 3.2*10^7 / 36 = 0.0888*10^7 = 88.8*10^4$

$w = 9.43*10^2 = 943 rad / s$

Thus,

943 rad / s ≈ 9000 rpm

6 0

3 years ago

A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original

lisov135 [29]

Answer:

P = 7.28 N.s

Explanation:

given,

initial momentum of cue ball in x- direction,P₁ = 9 N.s

momentum of nine ball in x- direction, P₂ = 2 N.s

momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s

momentum of the cue after collision = ?

using conservation of momentum

in x- direction

P₁ + p = x + P₂

p is the initial momentum of the nine balls which is equal to zero.

9 + 0 = x + 2

x = 7 N.s

momentum in x-direction.

equating along y-direction

P'₁ + p = y + P'₂

0 + 0 = y + 2

y = -2 N.s

the momentum of the cue ball after collision is equal to resultant of the momentum .

$P = \sqrt{x^2+y^2}$

$P = \sqrt{7^2+(-2)^2}$

P = 7.28 N.s

the momentum of the cue ball after collision is equal to P = 7.28 N.s

7 0

3 years ago

A car with mass 2.0×10 3 kg traveling east at a speed of 20 m/s collides at an intersection with a2.5×10 3 kg van traveling nort

lys-0071 [83]

When analyzing inelastic collisions, we need to consider the law of conservation of momentum, which states that the total momentum, p, of the closed system is a constant. In the case of inelastic collisions, the momentum of the combined mass after the collision is equal to the sum of the momentum of each of the initial masses.

p1+p2+...=pf

In our case we only have two masses, which makes our problem fairly simple. Lets plug in the formula for momentum; p=mv.

m1v1+m2v2=(m1+m2)vf

To find the velocity of the combined mass we simply rearrange the terms.

vf=m1v1+m2v2m1+m2

Plug in the values given in the problem.

vf=(3.0kg)(1.4m/s)+(2.0kg)(0m/s)03.0kg+2.0kg

vf=.84m/s

7 0

3 years ago