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const2013 [10]
3 years ago
13

Need an explanation please. Brainliest will be awarded.

Physics
1 answer:
Maurinko [17]3 years ago
7 0

We're adding two vectors here.  The first is 300 Newtons to the right, which we can write as (300, 0), meaning 300 to the right, 0 up.

The second is 300 at let's say a 45 degree angle down.  For the components we have an isosceles right triangle with hypotenuse 300, so the components are both magnitude 300/√2 = 150√2.  So we can write this vector (150√2, -150√2), the negative sign because it points down in the y direction.

Adding is componentwise.  The resulting force is (300+150√2, -150√2).

That has square magnitude

r² = (300+150√2)² + (-150√2)² = 150² ( (2+√2)² + (√2)² )

= 150²( (6 + 4√2) + 2)

= 300²(2+√2)

so

r = 300 √(2+√2) Newtons

That's the answer; I'm not sure if your class expects a calculator approximation, which is 554.3 Newtons.

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Answer:

T/√8

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For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

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If all colors of light are mixed together, what color will he seen?
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Black. or a dark brown.

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Which statement describes why scientists notation is useful
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On the list of choices that you provided, there is no such statement.

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If an object is thrown in an upward direction from the top of a building 160 ft. High at an initial speed of 21.82 mi/h what is
viktelen [127]
To solve this problem we are going to use tow kinematic equations for falling objects.
1. Kinematic equation for final velocity: V_{f}=V_{i}+gt
where
V_{f} is the final velocity 
V_{i} is the initial velocity 
g is the acceleration due to gravity 32 \frac{ft}{s^2}
t is the time 
2. Kinematic equation for distance: d=V_{i}t+ \frac{1}{2} gt^2
where
d is the distance 
V_{i} is the initial velocity 
V_{f} is the final velocity
g is the acceleration due to gravity 32 \frac{ft}{s^2}
t is the time 

First, we are going to convert 21.82 mi/h to ft/s:
21.82 \frac{mi}{h} =31.21 \frac{ft}{s}

Next, we are going to use the first equation to find how long it takes for the rock to reach its maximum height.
We know for our problem that the object is thrown in upward direction, so its velocity at its maximum height (before falling again) will be zero; therefore: V_{f}=0. We also know that it initial speed is 31.21 ft/s, so V_{i}=31.21. Lets replace those values in our formula to find t:
V_{f}=V_{i}+gt
0=31.21+(-32)t
-32t=-31.21
t= \frac{-31.21}{-32}
t=0.98seconds

Next, we are going to use that time in our second kinematic equation to find the distance the object reach at its maximum height:
d=V_{i}t+ \frac{1}{2} gt^2
d=31.21(0.98)+ \frac{1}{2} (-32)(0.98)^2
d=15.22ft 

Now we can add the height of the building and the maximum height of the object:
d=160+15.22=175.22ft

Next, we are going to use that height (distance) in our second kinematic equation one more time to fin how long it takes for the object to fall from its maximum height to the ground:
d=V_{i}t+ \frac{1}{2} gt^2
175.22=31.21t+ \frac{1}{2} (32)t^2
16t^2+31.21t-175.22=0
t=2.47 or t=-4.43
Since time cannot be negative, t=2.47 is the time it takes the object to fall to the ground. 

Finally, we can use that time in our first kinematic equation to find the final speed of the object when it hits the ground:
V_{f}=V_{i}+gt
V_{f}=31.21+(32)(2.47)
V_{f}=110.25 ft/s

We can conclude that the speed of the object when it hits the ground is 110.25 ft/s


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Answer:

24kgm/s

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momentum(p)=mass×velocity

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