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3 years ago

How efficient is a pulley system if an operator has to pull 2.5m of rope to lift a 250 N pail of water a distance of 4.5 m?

Physics

1 answer:

Alik [6]3 years ago

4 0

Answer:

the pulley system is very efficient

Explanation:

Given;

load, L = 250 N

distance moved by the load, a = 4.5 m

distance moved by the effort, e = 2.5 m

let the force or effort applied = F

Apply the principle of conservation of energy;

F x e = L x a

F = (L x a) / e

F = (250 x 4.5) / 2.5

F = 450 N

The efficient of the pulley system;

E = Output force / Input force

E = (450 x 2.5) / (250 x 4.5)

E = 1 = 100%

Therefore, the pulley system is very efficient

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A 750-kg automobile is moving at 16.8 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car

anygoal [31]

Answer:h=19.4 m

Explanation:

Given

mass of automobile $m=750\ kg$

Initial height of automobile $h_o=5\ m$

Velocity at this instant $v=16.8\ m/s$

If the car stops somewhere at a height $h$

Thus conserving total energy we get

$K_i+U_i=K_f+U_f$

$\frac{1}{2}mv^2+mgh_o=\frac{1}{2}m(0)^2+mgh$

$\frac{v^2}{2g}+h_o=h$

$h=5+\frac{16.8^}{2\times 9.8}$

$h=5+14.4$

$h=19.4\ m$

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The Moment of Inertia of the Disc is represented by $I = \frac{15}{32}\cdot M\cdot R^{2}$ . (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

$I = I_{D} - I_{H}$ (1)

Where:

$I_{D}$ - Moment of inertia of the Disk.

$I_{H}$ - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

$I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)$ (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ( $m$ ):