The supplement of the angle is 16.
To find a supplement, you take the measure of the angle you know and subtract that from 180. So 180-164=16.
Hope this helps! :D
Let x = number
2(x-2)=3(x+6)
2x-4=3x+18
2x-3x=18+4
-x=22
x=-22
The equation for volume is V= (pi)(R^2)xH
For Pi use 3.14
So switch the variables for the numbers that we know
V= (3.14)(3^2)x4
3^2= 9
3.14 x 9= 28.26
28.26x9 = 113.04
113.04 to the nearest tenth would be 113.
Answer:
Point N(3,0) is equidistant from A and B.
Step-by-step explanation:
In order to check whether the point is equidistant from A and B, it is required to measure the distance of A and B from each point. The formula for distance is:
d= √((x_2-x_(1))^2+(y_2-y_(1))^2 )
For J
AJ= √((-4-0)^2+(-5+4)^2 )
=√((-4)^2+(-1)^2 )
= √(16+1)
= √17 units
BJ=√((-4+2)^2+(-5-0)^2 )
=√((-2)^2+(-5)^2 )
= √(4+25)
= √29 units
Point J is not equidistant from A and B.
For K
AK= √((-3-0)^2+(0+4)^2 )
=√((-3)^2+(4)^2 )
= √(9+16)
= √25 units
=5
BK=√((-3+2)^2+(0-0)^2 )
=√((-1)^2+(0)^2 )
= √(1+0)
= √1
=1 unit
Point K is not equidistant from A and B.
For M
AM= √((0-0)^2+(0+4)^2 )
=√((0)^2+(4)^2 )
= √(0+16)
= √16
=4 units
BM=√((0+2)^2+(0-0)^2 )
=√((2)^2+(0)^2 )
= √(4+0)
= √4
=2 units
Point M is not equidistant from A and B.
For N
AN= √((3-0)^2+(0+4)^2 )
=√((3)^2+(4)^2 )
= √(9+16)
= √25
=5 units
BN=√((3+2)^2+(0-0)^2 )
=√((5)^2+(0)^2 )
= √(25+0)
= √25
=5 units
As point N's distance is equal from A and B, Point N is equidistant from A and B.
.
Answer: 0.343
Step-by-step explanation:
6-2.657=3.343 subtract 3 you get 0.343
